对按时间先后顺序的列表按同一天进行分组

最新推荐文章于 2023-07-25 18:16:22 发布

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最新推荐文章于 2023-07-25 18:16:22 发布

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分类专栏：算法

本文链接：https://blog.youkuaiyun.com/nextstudio/article/details/42122377

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本文介绍了如何将一个按时间先后顺序排列的列表，根据日期进行分组，将同一天的数据归为一类。通过实现代码，详细展示了具体的分组逻辑和步骤。

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实现代码：

- (NSMutableArray *)reGroupDataSoure:(NSArray *)originArr
{
    NSDateFormatter *dateFmt = [[NSDateFormatter alloc] init];
    [dateFmt setDateFormat:@"yyyy-MM-dd"];
    NSMutableArray *groupsArr = [NSMutableArray new];
    int i = 0;
    int j;
    for (;i < [originArr count] - 1;) {
        NSMutableArray *sameArr = [NSMutableArray new];
        NSDictionary *dic = [originArr objectAtIndex:i];
        [sameArr addObject:dic];
        long long ct = [[dic objectForKey:@"ct"] longLongValue];
        NSDate *ctDate = [NSDate dateWithTimeIntervalSince1970:ct/1000];
        NSString *ctString = [dateFmt stringFromDate:ctDate];
        //NSLog(@"day -- %@",ctString);
        j = i + 1;<p class="p1"><span class="s1"><span style="white-space:pre">	</span>if</span><span class="s2"> (j == [<span style="font-family: Arial, Helvetica, sans-serif;">originArr   </span></span><span class="s4">count</span><span class="s2">]) {</span></p><p class="p1"><span class="s2">            </span><span class="s1">if</span><span class="s2"> (j == </span><span class="s5">1</span><span class="s2">) {</span></p><p class="p2"><span class="s6">                </span><span class="s2">//</span><span class="s7">只有一个元素</span></p><p class="p3"><span class="s6">                [<span style="font-family: Arial, Helvetica, sans-serif;">groupsArr  </span></span><span class="s4">addObject</span><span class="s6">:</span><span class="s2">originArr</span><span class="s6">];</span></p><p class="p1"><span class="s2">            }</span></p><p class="p1"><span class="s2">            </span><span class="s1">return groupsArr</span><span class="s2">;</span></p><p class="p1"><span class="s2">        }</span></p>        for (; j < [originArr count];) {
            NSDictionary *jDic = [originArr objectAtIndex:j];
            long long jct = [[jDic objectForKey:@"ct"] longLongValue];
            NSDate *jctDate = [NSDate dateWithTimeIntervalSince1970:jct/1000];
            NSString *jctString = [dateFmt stringFromDate:jctDate];
            if ([jctString isEqualToString:ctString]) {
                //同一组
                [sameArr addObject:jDic];
                j++;
                if (j == [originArr count]) {
                    [groupsArr addObject:sameArr];
                    return groupsArr;
                }
            }
            else
            {
                i = j;
                [groupsArr addObject:sameArr];
                break;
            }
        }
    }
    return groupsArr;
}