CodeForces 611B - New Year and Old Property(搜索)

最新推荐文章于 2019-01-20 11:21:15 发布

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博客讲述了CodeForces中编号为611B的一道编程题目，该题目要求求解在给定的两个年份之间，有多少年的二进制表示只包含一个零。输入包含两个整数，输出符合条件的年份数量。解决方案是通过深度优先搜索遍历所有只含一个零的二进制数。

B. New Year and Old Property
time limit per test2 seconds
memory limit per test256 megabytes
inputstandard input
outputstandard output
The year 2015 is almost over.

Limak is a little polar bear. He has recently learnt about the binary system. He noticed that the passing year has exactly one zero in its representation in the binary system — 201510 = 111110111112. Note that he doesn’t care about the number of zeros in the decimal representation.

Limak chose some interval of years. He is going to count all years from this interval that have exactly one zero in the binary representation. Can you do it faster?

Assume that all positive integers are always written without leading zeros.

Input
The only line of the input contains two integers a and b (1 ≤ a ≤ b ≤ 1018) — the first year and the last year in Limak’s interval respectively.

Output
Print one integer – the number of years Limak will count in his chosen interval.

Examples
input
5 10
output
2
input
2015 2015
output
1
input
100 105
output
0
input
72057594000000000 72057595000000000
output
26
Note
In the first sample Limak’s interval contains numbers 510 = 1012, 610 = 1102, 710 = 1112, 810 = 10002, 910 = 10012 and 1010 = 10102. Two of them (1012 and 1102) have the described property.

题意：
给出两个数，问这两个数中有多少个数的二进制只有一个0.

解题思路：
DFS所有只有一个0的二进制的数即可。

AC代码：

#include<bits/stdc++.h>
using namespace std;
long long a,b;
int cnt = 0;
void fun(long long check,bool flag)
{
    if(check > b)   return ;
    if(check>=a && check <= b && flag)  cnt++;
    if(!flag)   fun(check<<1,1);
    fun(check<<1|1,flag);
}
int main()
{
    cin>>a>>b;
    fun(1,0);
    cout<<cnt;
    return 0;
}