#include <stdio.h>
int main ( )
{
int year, month, days;
printf("请输入年、月: ");
scanf("%d %d", &year, &month);
switch(month)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
days = 31;
break;
case 4:
case 6:
case 9:
case 11:
days = 30;
break;
case 2:
if(year%4==0 && year%100!=0 ||year%400==0)
days = 29;
else
days =28;
}
printf("%d 年 %d 月共有 %d 天。\n", year, month, days);
return 0;
}
利用switch语句解决问题:年月日
最新推荐文章于 2022-05-13 17:59:15 发布