PROBLEM:
Write a SQL query to get the second highest salary from the Employee table.
+----+--------+ | Id | Salary | +----+--------+ | 1 | 100 | | 2 | 200 | | 3 | 300 | +----+--------+
For example, given the above Employee table, the query should return 200 as the second highest salary. If there is no second highest salary, then the query should return null.
+---------------------+ | SecondHighestSalary | +---------------------+ | 200 | +---------------------+
SOLVE:
# Write your MySQL query statement below
select (
select distinct Salary
from Employee
order by Salary Desc
limit 1 , 1
)as SecondHighestSalary# Write your MySQL query statement below
SELECT max(Salary) AS SecondHighestSalary
FROM Employee
WHERE Salary < (SELECT max(Salary)
FROM Employee)分析:即使表中没有数据,最后也会返回null。原理,我也不知道!
本文提供了一种使用SQL从员工表中查询第二高薪资的方法。通过两种不同的查询方式,一种利用子查询和LIMIT关键字,另一种则通过比较最大薪资来实现。即使表中没有数据,查询结果也会返回null。
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