iOS查找子字符串(含多个字符串)在父字符串中的所有位置

方法的调用
NSArray *array = [self calculateSubStringCount:@"abcd1234556abcd" str:@"abcd"];

方法的实现

/**
 查找子字符串在父字符串中的所有位置
 @param content 父字符串
 @param tab 子字符串
 @return 返回位置数组
 */
- (NSMutableArray*)calculateSubStringCount:(NSString *)content str:(NSString *)tab {
    int location = 0;
    NSMutableArray *locationArr = [NSMutableArray new];
    NSRange range = [content rangeOfString:tab];
    if (range.location == NSNotFound){
        return locationArr;
    }
    NSInteger point = 0;
    //声明一个临时字符串,记录截取之后的字符串
    NSString * subStr = content;
    while (range.location != NSNotFound) {
        if (locationArr.count > 0) {
            point = range.location + locationArr.count * tab.length;
        } else {
            point = range.location;
        }
        //记录位置
        NSNumber *number = [NSNumber numberWithUnsignedInteger:point];
        [locationArr addObject:number];

        //每次记录之后,把找到的字串截取掉
        subStr = [subStr substringFromIndex:range.location + range.length];
        NSLog(@"subStr %@",subStr);
        range = [subStr rangeOfString:tab];
        NSLog(@"rang %@",NSStringFromRange(range));
    }
    return locationArr;
}