数值的整数次方

给定一个double类型的浮点数base和int类型的整数exponent。求base的exponent次方。

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public class Solution {
    public double Power(double base, int exponent) {
        if(equal(base, 0.0) && exponent < 0)
            return 0.0;
        int absExponent = exponent;
        if(exponent < 0)
            absExponent = -exponent;
        double result = powerWithExponent(base, absExponent);
        if(exponent < 0)
            result = 1.0 / result;
        return result;
  }
    private boolean equal(double num1, double num2)
    {
       if((num1 - num2 > -0.0000001) && (num1 - num2 < 0.0000001))
           return true;
        else
            return false;
    }
    private double powerWithExponent(double base, int exponent)
        {
        double result = 1.0;
        for(int i = 1; i <= exponent; ++i)
            {
            result *= base;
        }
        return result;
    }
}