UVa 1585 Score(得分,水题)

本文介绍了一个简单的算法,用于计算一种特殊格式的客观测试答案得分。该算法读取由'O'和'X'组成的字符串,'O'代表正确答案,'X'代表错误答案。对于每个正确的答案,其分数等于它自身加上连续的前面正确答案的数量。

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Description

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There is an objective test result such as ``OOXXOXXOOO". An `O' means a correct answer of a problem and an `X' means a wrong answer. The score of each problem of this test is calculated by itself and its just previous consecutive `O's only when the answer is correct. For example, the score of the 10th problem is 3 that is obtained by itself and its two previous consecutive `O's.

Therefore, the score of ``OOXXOXXOOO" is 10 which is calculated by ``1+2+0+0+1+0+0+1+2+3".

You are to write a program calculating the scores of test results.

Input 

Your program is to read from standard input. The input consists of T test cases. The number of test cases T is given in the first line of the input. Each test case starts with a line containing a string composed by ` O' and ` X' and the length of the string is more than 0 and less than 80. There is no spaces between ` O' and ` X'.

Output 

Your program is to write to standard output. Print exactly one line for each test case. The line is to contain the score of the test case.

The following shows sample input and output for five test cases.

Sample Input 

5 
OOXXOXXOOO 
OOXXOOXXOO 
OXOXOXOXOXOXOX 
OOOOOOOOOO 
OOOOXOOOOXOOOOX

Sample Output 

10 
9 
7 
55 
30
	
	
 
 
 
 
 
 
 
 
这题水题一个,还没有看题目描述只看示例就明白它要干啥,没啥好说的,直接上代码。。。= =
	
	
 
 
 
 
 
 
 
 
#include <iostream>
#include <cstring>

using namespace std;

int main()
{
	char str[111];
	int n,sum,i,len,t;
	cin>>n;
	while(n--)
	{
		sum=0;
		cin>>str;
		len=strlen(str);
		for(t=1,i=0;i<len;i++)
		{
			if(str[i]=='O')
			{
				sum+=t;		//将计数变量加进累加器里。
				t++;
			}
			else if(str[i]=='X')	//遇到X则计数变量归位。
				t=1;
		}
		cout<<sum<<endl;
	}

	return 0;
}

 
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