python第三次作业

最新推荐文章于 2024-10-04 00:07:21 发布

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#python #开发语言

本文展示了四个不同的Python循环模式，用于打印特定形状。接着是一个简单的石头剪刀布游戏，通过Python实现玩家与电脑的互动。最后，文章还包含两个数学计算示例，用以求解e和π的近似值。

1.四个循环模式

1.1

n = int(input("请输入你要打印的行数： "))
for i in range(1, n + 1):
    spce_num = n - i
    for k in range(spce_num, 0):
        print(" ", end="")
    for j in range(1, i + 1):
        print(j, end=" ")
    print("")

1.2

n = int(input("请输入你要打印的行数： "))
for i in range(n, 0, -1):
    spce_num = n - i
    for k in range(spce_num, 0):
        print(" ", end="")
    for j in range(1, i + 1):
        print(j, end=" ")
    print("")

1.3

n = int(input("请输入你要打印的层数："))
for i in range(1, n+1):
    spce_num = n - i
    for k in range(0, spce_num):
        print(" ", end="")
    for j in range(i, 0, -1):
        print(j, end="")
    print()

1.4

n = int(input("请输入你要打印的行数："))
for i in range(n, 0, -1):
    spce_num = n - i
    for k in range(0, spce_num):
        print(" ", end="")
    for j in range(1, i+1):
        print(j, end="")
    print("")

2.石头剪刀布游戏

import random as r

c_point = 0
h_point = 0
while True:
    c = r.randint(1, 3)
    h = int(input("请出拳，1代表石头，2代表剪刀，3代表布"))
    if c == 1:
        if h == 1:
            print("电脑出石头，玩家出石头，打平")
        elif h == 2:
            c_point += 1
            print("电脑出石头，玩家出剪刀，电脑胜")
        elif h == 3:
            h_point += 1
            print("电脑出石头，玩家出布，玩家胜")
    if c == 2:
        if h == 2:
            print("电脑出剪刀，玩家出剪刀，平局")
        elif h == 1:
            h_point += 1
            print("电脑出剪刀，玩家出石头，玩家胜")
        elif h == 3:
            c_point += 1
            print("电脑出剪刀，玩家出布，电脑胜")
    if c == 3:
        if h == 3:
            print("电脑出布，玩家出布，打平")
        elif h == 2:
            h_point += 1
            print("电脑出布，玩家出剪刀，玩家胜")
        elif h == 1:
            c_point += 1
            print("电脑出布，玩家出石头，电脑胜")

    if c_point == 2 or h_point == 2:
        if c_point > h_point:
            print("电脑获胜")
            break
        else:
            print("玩家获胜")
            break

3.e的近似值

sum = 1
a = 1
b = 1
while 1 / a > 1e-6:
        a = a * b
        sum = sum + 1 / a
        b += 1
print("sum=%.6f" % sum)

4.π的近似值

pi = 1
f = -1
i = 3
while 1 / i > 1e-6:
    pi = pi + 1 / i * f
    i += 2
    f = -f
print("pi=%.6f" % (pi * 4))