Returning unescaped Json in MVC with Json.Net-优快云博客

本文详细介绍了如何在使用Json.NET时避免对象序列化两次的问题，并提供了一个自定义ActionResult类来解决此问题。同时，文章还强调了避免在序列化过程中重复操作的重要性。

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http://stackoverflow.com/questions/7382265/returning-unescaped-json-in-mvc-with-json-net

The object is already serialized by Json.NET, and when you pass it to Json() it gets encoded twice. If you must use Json.NET instead of the built in encoder, then the ideal way to handle this would be to create a custom ActionResult accepts the object and calls Json.net internally to serialize the object and return it as an application/json result.

EDIT

This code is for the solution mentioned above. It's untested, but should work.

public class JsonDotNetResult : ActionResult
{
    private object _obj { get; set; }
    public JsonDotNetResult(object obj)
    {
        _obj = obj;
    }

    public override void ExecuteResult(ControllerContext context)
    {
        context.HttpContext.Response.AddHeader("content-type", "application/json");
        context.HttpContext.Response.Write(JsonConvert.SerializeObject(_obj));
    }
}

and in your controller just do:

return new JsonDotNetResult(result);

You are Jsoning it twice, the Json method is json serializing your already converted string. If you want to use JsonConvert then write that directly to the response stream.