Problem Description
Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.
Now please try your lucky.
Input
The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);
Output
For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.
Sample Input
2 100 -4
Sample Output
1.6152 No solution!
Author
Redow
二分查找题~
<span style="font-size:10px;">//HDOJ_2199
//20150916
#include<iostream>
#include<cmath>
#include<iomanip>
using namespace std;
double f(double x)
{
return 8*pow(x,4)+7*pow(x,3)+2*pow(x,2)+3*pow(x,1)+6;
}
int main()
{
int T;
double Y,l,r,m;
cin>>T;
while(T--)
{
cin>>Y;
if(f(0)<=Y&&f(100)>=Y)
{
l=0;
r=100;
while(l-r<-1e-6)
{
m=(l+r)/2;
double ans=f(m);
if(ans>Y)
r=m-(1e-7);
else
l=m+(1e-7);
}
cout<<fixed<<setprecision(4)<<(l+r)/2<<endl;
}
else
cout<<"No solution!"<<endl;
}
}</span>