You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
Note: Given n will be a positive integer.
解法:利用DP动态规划,由于dp[i] = dp[i-2] + dp[i-1]class Solution {
public:int climbStairs(int n) {
if (n == 1) return 1;
int dp[n+1];
dp[1] = 1;
dp[2] = 2;
for (int i = 3; i <= n ; i++) {
dp[i] = dp[i-1] + dp[i-2];
}
return dp[n];
}
};