ACboy needs your help again!
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 2452 Accepted Submission(s): 1254Problem DescriptionACboy was kidnapped!! he miss his mother very much and is very scare now.You can't image how dark the room he was put into is, so poor :(.As a smart ACMer, you want to get ACboy out of the monster's labyrinth.But when you arrive at the gate of the maze, the monste say :" I have heard that you are very clever, but if can't solve my problems, you will die with ACboy."The problems of the monster is shown on the wall:Each problem's first line is a integer N(the number of commands), and a word "FIFO" or "FILO".(you are very happy because you know "FIFO" stands for "First In First Out", and "FILO" means "First In Last Out").and the following N lines, each line is "IN M" or "OUT", (M represent a integer).and the answer of a problem is a passowrd of a door, so if you want to rescue ACboy, answer the problem carefully! InputThe input contains multiple test cases.The first line has one integer,represent the number oftest cases.And the input of each subproblem are described above. OutputFor each command "OUT", you should output a integer depend on the word is "FIFO" or "FILO", or a word "None" if you don't have any integer. Sample Input4
4 FIFO
IN 1
IN 2
OUT
OUT
4 FILO
IN 1
IN 2
OUT
OUT
5 FIFO
IN 1
IN 2
OUT
OUT
OUT
5 FILO
IN 1
IN 2
OUT
IN 3
OUT
Sample Output
1 2 2 1 1 2 None 2 3STL的应用贴一下队列和栈的基本用法代码:#include<iostream> #include<queue> #include<stack> #include<cstdio> #include<cstring> #include<ctype.h> using namespace std; int n; void FIFO () { queue<int> ss; char ch[10]; int p,i; for (i=0; i<n; i++) { scanf("%s", ch); if (strcmp(ch,"IN")==0) { cin>>p; ss.push(p); } else { if (!ss.empty()) { cout<<ss.front()<<endl; ss.pop(); } else cout<<"None"<<endl; } } return; } void FILO () { stack<int> ss; char ch[10]; int p,i; for (i=0; i<n; i++) { scanf("%s", ch); if (strcmp(ch,"IN")==0) { cin>>p; ss.push(p); } else { if (!ss.empty()) { cout<<ss.top()<<endl; ss.pop(); } else cout<<"None"<<endl; } } return; } int main () { int t,i; string st; char ch[10]; cin>>t; while (t--) { cin>>n; cin>>st; if (st=="FIFO") FIFO(); else if (st=="FILO") FILO(); } return 0; }
本文探讨如何运用先进算法成功解救被困在怪物迷宫中的AC男孩,涉及队列和栈的FIFO与FILO原理,提供详细编程实现及应用案例。
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