问题描述
Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
For example,
Given input array A = [1,1,2],
Your function should return length = 2, and A is now [1,2].
解决方案
class Solution {
public:
int removeDuplicates(int A[], int n) {
for( int i = 1; i < n; ++i ) {
if( A[i] == A[i - 1] ) {
for( int k = i; k < n; ++k ) {
A[k - 1] = A[k];
}
--n;
--i;
}
}
return n;
}
};
本文介绍了一个C++程序,用于在不使用额外空间的情况下从已排序数组中移除重复元素,并返回处理后的数组长度。示例中给出了具体实现方法及一个例子。
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