282.使用特殊打字机键入单词的最少时间

class Solution {
    public int minTimeToType(String word) {
        int res=0;
        int index=1;
        for(int i=0;i<word.length();i++){
            int now=word.charAt(i)-'a'+1;
            int distance=Math.abs(now-index);
            if(distance<13){
                res+=distance;
            }
            else{
                res+=(26-distance);
            }
            index=now;
        }
        return res+word.length();
    }
}

class Solution(object):
    def minTimeToType(self, word):
        res = 0
        index = 1
        for c in word:
            now = ord(c) - ord('a') + 1
            distance = abs(now - index)
            if distance < 13:
                res += distance
            else:
                res += (26 - distance)
            index = now
        return res + len(word)