ListView

最新推荐文章于 2025-12-16 15:21:13 发布

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在Android中，有三种简单的方法可以使用ListView。

使用ArrayAdapter

ArrayAdapter是最简单的适配器，它将字符串数组的内容显示在ListView中。

ListView listView = (ListView) findViewById(R.id.listView);
String[] values = new String[] { "Android", "iPhone", "WindowsMobile", "BlackBerry", "WebOS" };
ArrayAdapter<String> adapter = new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, values);
listView.setAdapter(adapter);

使用SimpleAdapter

SimpleAdapter可以用于将更复杂的数据绑定到ListView。

ListView listView = (ListView) findViewById(R.id.listView);
List<Map<String, String>> data = new ArrayList<Map<String, String>>();
Map<String, String> item = new HashMap<String, String>();
item.put("title", "Google");
item.put("description", "Google search");
data.add(item);

SimpleAdapter adapter = new SimpleAdapter(this, data, android.R.layout.simple_list_item_2, new String[] {"title", "description"}, new int[] {android.R.id.text1, android.R.id.text2});
listView.setAdapter(adapter);

使用自定义Adapter

如果你需要更复杂的布局或行为，你可以创建自定义的Adapter。

public class MyAdapter extends ArrayAdapter<String> {
private Context context;

public MyAdapter(Context context, int resource, List<String> objects) {
super(context, resource, objects);
this.context = context;
}

@Override
public View getView(int position, View convertView, ViewGroup parent) {
LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
View rowView = inflater.inflate(android.R.layout.simple_list_item_1, parent, false);
TextView textView = (TextView) rowView.findViewById(android.R.id.text1);
textView.setText(getItem(position));
return rowView;
}
}

ListView listView = (ListView) findViewById(R.id.listView);
List<String> values = new ArrayList<String>();
values.add("Android");
values.add("iPhone");
values.add("WindowsMobile");
values.add("BlackBerry");
values.add("WebOS");
MyAdapter adapter = new MyAdapter(this, android.R.layout.simple_list_item_1, values);
listView.setAdapter(adapter);