JS删除树型结构中的某些满足条件的节点

   function deleteNameIsNullNode(data) {
        const tree = data.filter(node => {
            if (!node.name) {
                return false
            }
            // 如果当前节点有子节点，则递归调用
            if (node.children && node.children.length > 0) {
                node.children = deletenameNode(node.children)
            }
            return true
        })
        return tree
    }
    const a = deletenameNode([
        {
            title: 'a',
            name: 'a',
            children: [
                {
                    title: 'c',
                    name: 'c',
                    children: [
                        { title: 'e', name: 'e' },
                        { title: 'f', name: '' },
                    ],
                },
                { title: 'd', name: '' },
                { title: 'e', name: 'e' },
            ],