Given a string s and a string t, check if s is subsequence of t.
You may assume that there is only lower case English letters in both s and t. t is potentially a very long (length ~= 500,000) string, and s is a short string (<=100).
A subsequence of a string is a new string which is formed from the original string by deleting some (can be none) of the characters without disturbing the relative positions of the remaining characters. (ie, "ace" is a subsequence of "abcde" while "aec" is not).
Example 1:
s = "abc", t = "ahbgdc"
Return true
.
Example 2:
s = "axc", t = "ahbgdc"
Return false
.
直接从s和t的首端开始遍历比较字符是否相等即可,如果不等,则增加在t中的下标位置;如果相等,则同时增加在s和t中的下标位置。如果t中的指标位置增长到了t的末尾,而s中的指标还没有增长的末尾,则返回false。如果s中的指标先增长到了末尾,则返回true。
代码:
bool isSubsequence(string s, string t) {int i, j, last = 0;
for (i = 0; i < s.size(); i++) {
for (j = last; j < t.size(); j++) {
if (s[i] == t[j]) {
last = j + 1;
break;
}
}
if (j == t.size()) return false;
}
return true;
}