文章作者:Tyan
博客:noahsnail.com | 优快云 | 简书
1. 问题描述
Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Example 1:
Input: [1,3,5,6], 5
Output: 2
Example 2:
Input: [1,3,5,6], 2
Output: 1
Example 3:
Input: [1,3,5,6], 7
Output: 4
Example 4:
Input: [1,3,5,6], 0
Output: 0
2. 求解
Solution(C++):
这道题就是一个二分查找问题。
class Solution {
public:
int searchInsert(vector<int>& nums, int target) {
int left = 0;
int right = nums.size() - 1;
int middle = 0;
while(left <= right) {
middle = (left + right) / 2;
if(nums[middle] < target) {
left = middle + 1;
} else if (nums[middle] > target) {
right = middle - 1;
}
else {
return middle;
}
}
return left;
}
};

本文详细介绍了二分查找算法的应用场景及其实现方式。通过解决一个具体的问题——在有序数组中查找目标值或确定插入位置,文章提供了一个清晰的C++代码示例。此算法适用于已排序且不含重复元素的数组。
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