LeetCode 205. Isomorphic Strings

最新推荐文章于 2025-05-14 15:08:29 发布

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最新推荐文章于 2025-05-14 15:08:29 发布

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本文链接：https://blog.youkuaiyun.com/Queue_notes/article/details/78073539

本文介绍了一种算法，用于判断两个给定的字符串是否为同构字符串。通过使用两个映射表来跟踪不同字符串间的字符对应关系，确保了所有出现的相同字符都被一致地替换。

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Given two strings s and t, determine if they are isomorphic.

Two strings are isomorphic if the characters in s can be replaced to get t.

All occurrences of a character must be replaced with another character while preserving the order of characters. No two characters may map to the same character but a character may map to itself.

For example,
Given "egg", "add", return true.

Given "foo", "bar", return false.

Given "paper", "title", return true.

分析：

定义两个键值对m1,m2。m1表示s到t的映射，m2表示t到s的映射，如果当前字符已经被映射，并且值不等于

class Solution {
public:
    bool isIsomorphic(string s, string t) {
        int n=s.length();
        map<char,char> m1;
        map<char,char> m2;
        cout<<n<<endl;
        for(int i=0;i<n;i++){
            if((m1.count(s[i])>0&& m1[s[i]] != t[i] )||( m2.count(t[i])>0&& m2[t[i]] != s[i]))
                return false;
            m1[s[i]]=t[i];
            m2[t[i]]=s[i];
        }
        return true;
    }
};