Oracle sql面试题二

Student(S#,Sname,Sage,Ssex) 学生表 
   
 
Course(C#,Cname,T#) 课程表   
SC(S#,C#,score) 成绩表   

Teacher(T#,Tname) 教师表   

问题
1、查询“001”课程比“002”课程成绩高的所有学生的学号   
select  a.S# 
from (select s#,score from SC where C#='001') a,
 (select s#,score from SC where C#='002') b 
where  a.score>b.score and a.s#=b.s#; 
 2、查询平均成绩大于60分的同学的学号和平均成绩   
select S#,avg(score) 
from sc   
group by S# having avg(score) >60;   
   
 
3、查询所有
同学的学号、姓名、选课数、总成绩 
 
select Student.S#,Student.Sname,count(SC.C#),sum(score) 
from Student left Outer
 join SC on Student.S#=SC.S#   
group by Student.S#,Sname 
 
4、查询姓“李”的老师的个数   
select count(distinct(Tname))  

from Teacher    
where Tname like '李%';    
  
5、查询没学过“叶平”老师课的同学的学号、姓名    
select Student.S#,Student.Sname   
from Student    
where S# not in (select distinct( SC.S#) from SC,Course,Teacher where  
SC.C#=Course.C# and Teacher.T#=Course.T# and Teacher.Tname='叶平'); 
   
 
  
6、查询学过“001”并且也学过编号“002”课程的同学的学号、姓名 
   
 
select Student.S#,Student.Sname 
   
 
from Student,SC    
where Student.S#=SC.S# and SC.C#='001'and exists( Select * from SC as SC_2 
where SC_2.S#=SC.S# and SC_2.C#='002');   
7、查询学过“叶平”老师所教的所有课的同学的学号、姓名   
select S#,Sname   
from Student   
where S# in 
   
 
 (select S#   
 from SC ,Course ,Teacher 
   
 
 where SC.C#=Course.C# and Teacher.T#=Course.T# and 
Teacher.Tname='叶平' group by S# having count(SC.C#)=(select 
count(C#) from Course,Teacher  where Teacher.T#=Course.T# and 
Tname='叶平'));    
  
8、查询所有课程成绩小于60分的同学的学号、姓名   
select S#,Sname    
from Student 
   
 where S# not in (select Student.S# from Student,SC where S.S#=SC.S# and 
score>60);    
   
 
9、查询没有学全所有课的同学的学号、姓名    
select Student.S#,Student.Sname    
from Student,SC    
where Student.S#=SC.S#   
group by  Student.S#,Student.Sname having count(C#) <(select count(C#) 
from Course);    
   
10、查询至少有一门课与学号为“1001”的同学所学相同的同学的学号和姓名   
select S#,Sname 
   
 
from Student,SC 
   
 
where Student.S#=SC.S# and C# in select C# from SC where S#='1001';
   
 
    
11、删除学习“叶平”老师课的SC表记录

Delect SC    
from course ,Teacher     
where Course.C#=SC.C# and Course.T#= Teacher.T# and Tname='叶平';    
  
12、查询各科成绩最高和最低的分以如下形式显示课程ID最高分最低
分    
SELECT L.C# 课程ID,L.score 最高分,R.score 最低分    
FROM SC L ,SC R   
WHERE L.C# = R.C#    
and 
   
 
L.score = (SELECT MAX(IL.score)   
     FROM SC IL,Student  IM   
     WHERE IL.C# = L.C# and IM.S#=IL.S#    
     GROUP BY IL.C#)   
and 
   
 
R.Score = (SELECT MIN(IR.score)   
    FROM SC  IR    
    WHERE IR.C# = R.C# 
   
 
GROUP BY IR.C#  );   
  
13
、查询学生平均成绩及其名次 
  
SELECT 1+(SELECT COUNT( distinct 平均成绩)   
    FROM (SELECT S#,AVG(score) 平均成绩   
       FROM SC   
          GROUP BY S# ) T1 

   WHERE 平均成绩 > T2.平均成绩) 名次, S# 学生学号,平均成绩 
   
 
FROM (SELECT S#,AVG(score) 平均成绩 FROM SC GROUP BY S# ) T2 
   
 
ORDER BY 平均成绩 desc;   
    
14、查询各科成绩前三名的记录:(不考虑成绩并列情况)   
SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数   
FROM SC t1    
WHERE score IN (SELECT TOP 3 score   
           FROM SC    
           WHERE t1.C#= C# 
   
 
           ORDER BY score DESC)   
ORDER BY t1.C#;    
   
 
15、查询每门功成绩最好的前两名 
   
 
SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 分数    
FROM SC t1   
WHERE score IN (SELECT TOP 2 score 
   
 
          FROM SC   

 WHERE t1.C#= C#    
          ORDER BY score DESC ) 
   
 
ORDER BY t1.C#;
   
 
   在面试过程中多次碰到一道SQL查询的题目查询A(ID,Name)表中第31至
40条记录ID作为主键可能是不是连续增长的列完整的查询语句如下 
方法一   
select  top 10 *    
from A 
   
 
where ID >(select max(ID) from (select  top 30 ID from A order by 
ID )
 T
) order by ID 
方法二
   
 
select top 10 *  
from  A   
where ID not In (select top 30 ID from A order by ID)   
order by ID