5179 beautiful number

奥比中光Gemini335L SDK实战:从标定参数到3D点云转换 本文详细介绍了奥比中光Gemini 335L深度相机的SDK实战应用,重点讲解如何跳过繁琐的棋盘格标定,直接调用出厂预标定参数实现高效的3D点云转换。通过解析内参、外参获取及四种核心坐标转换模式,并结合OpenCV等工具,指导开发者快速将相机集成到机器人抓取、三维测量等项目中,实现开箱即用的3D视觉解决方案。 阅读详情

beautiful number

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 831    Accepted Submission(s): 536


Problem Description
Let A=∑ni=1ai∗10n−i(1≤ai≤9) ( n is the number of A 's digits). We call A as “beautiful number” if and only if a[i]≥a[i+1] when 1≤i<n and a[i] mod a[j]=0 when 1≤i≤n,i<j≤n (Such as 931 is a "beautiful number" while 87 isn't).
Could you tell me the number of “beautiful number” in the interval [L,R] (including L and R)?
 

Input
The fist line contains a single integer T (about 100), indicating the number of cases.
Each test case begins with two integers L,R(1≤L≤R≤109) .
 

Output
For each case, output an integer means the number of “beautiful number”.
 

Sample Input
  
2 1 11 999999993 999999999
 

Sample Output
  
10 2
 

Source


题意应该好理解的.. 低位是高位的因子
实验室的爸爸们和我讲要数位dp   
然鹅,我是打表做的...

打表代码:
#include <stdio.h>
#include <string.h>

int num[100]={0},inv[100]={0};
int mem(int);
int pow(int);
int main()
{
    int t,p=0;
        //int n,m;scanf("%d%d",&n,&m);
        for(int i=1;i<=1000000000;i++)
    {
        memset(num,0,sizeof(num));
        int d=mem(i);int flag=0;
        //printf("%d\n",d);
        for(int j=1;j<d-1;j++)
        {
            if(num[j]<num[j+1])flag=1;
            for(int k=j+1;k<d;k++)
            {
                if(num[k]==0){flag=1;break;}
                if(num[j]%num[k]!=0){flag=1;break;}
            }
            if(flag)break;
        }
        if(flag)continue;
        else
        {
            int sum=0;
            for(int j=1;j<d;j++)
            {
                sum=sum+num[j]*pow(d-1-j);
            }
            if(sum==i)p++,printf("%d,",i);
        }
    }

    printf("\n%d\n",p);



}
int mem(int n)
{
    int d=1;
    while(n)
    {
        inv[d++]=n%10;
        n=n/10;
    }
    int dd=1;
    for(int i=d-1;i>0;i--)num[dd++]=inv[i];
    //for(int i=1;i<d;i++)printf("%d ",num[i]);
    //printf("\n");
    return d;
}
int pow(int n)
{
    int sum=1;
    for(int i=1;i<=n;i++)sum*=10;
    return sum;
}

AC:
#include <cstdio>
#include <iostream>
#include <cstring>
#include <algorithm>
typedef long long LL;
using namespace std;
int dig[20][20]={0},sum[20];
int solve(int);
int main()
{
    
    int ans[1300]={1,2,3,4,5,6,7,8,9,11,21,22,31,33,41,42,44,51,55,61,62,63,66,71,77,81,82,84,88,91,93,99,111,211,221,222,311,331,333,411,421,422,441,442,444,511,551,555,611,621,622,631,633,661,662,663,666,711,771,777,811,821,822,841,842,844,881,882,884,888,911,931,933,991,993,999,1111,2111,2211,2221,2222,3111,3311,3331,3333,4111,4211,4221,4222,4411,4421,4422,4441,4442,4444,5111,5511,5551,5555,6111,6211,6221,6222,6311,6331,6333,6611,6621,6622,6631,6633,6661,6662,6663,6666,7111,7711,7771,7777,8111,8211,8221,8222,8411,8421,8422,8441,8442,8444,8811,8821,8822,8841,8842,8844,8881,8882,8884,8888,9111,9311,9331,9333,9911,9931,9933,9991,9993,9999,11111,21111,22111,22211,22221,22222,31111,33111,33311,33331,33333,41111,42111,42211,42221,42222,44111,44211,44221,44222,44411,44421,44422,44441,44442,44444,51111,55111,55511,55551,55555,61111,62111,62211,62221,62222,63111,63311,63331,63333,66111,66211,66221,66222,66311,66331,66333,66611,66621,66622,66631,66633,66661,66662,66663,66666,71111,77111,77711,77771,77777,81111,82111,82211,82221,82222,84111,84211,84221,84222,84411,84421,84422,84441,84442,84444,88111,88211,88221,88222,88411,88421,88422,88441,88442,88444,88811,88821,88822,88841,88842,88844,88881,88882,88884,88888,91111,93111,93311,93331,93333,99111,99311,99331,99333,99911,99931,99933,99991,99993,99999,111111,211111,221111,222111,222211,222221,222222,311111,331111,333111,333311,333331,333333,411111,421111,422111,422211,422221,422222,441111,442111,442211,442221,442222,444111,444211,444221,444222,444411,444421,444422,444441,444442,444444,511111,551111,555111,555511,555551,555555,611111,621111,622111,622211,622221,622222,631111,633111,633311,633331,633333,661111,662111,662211,662221,662222,663111,663311,663331,663333,666111,666211,666221,666222,666311,666331,666333,666611,666621,666622,666631,666633,666661,666662,666663,666666,711111,771111,777111,777711,777771,777777,811111,821111,822111,822211,822221,822222,841111,842111,842211,842221,842222,844111,844211,844221,844222,844411,844421,844422,844441,844442,844444,881111,882111,882211,882221,882222,884111,884211,884221,884222,884411,884421,884422,884441,884442,884444,888111,888211,888221,888222,888411,888421,888422,888441,888442,888444,888811,888821,888822,888841,888842,888844,888881,888882,888884,888888,911111,931111,933111,933311,933331,933333,991111,993111,993311,993331,993333,999111,999311,999331,999333,999911,999931,999933,999991,999993,999999,1111111,2111111,2211111,2221111,2222111,2222211,2222221,2222222,3111111,3311111,3331111,3333111,3333311,3333331,3333333,4111111,4211111,4221111,4222111,4222211,4222221,4222222,4411111,4421111,4422111,4422211,4422221,4422222,4441111,4442111,4442211,4442221,4442222,4444111,4444211,4444221,4444222,4444411,4444421,4444422,4444441,4444442,4444444,5111111,5511111,5551111,5555111,5555511,5555551,5555555,6111111,6211111,6221111,6222111,6222211,6222221,6222222,6311111,6331111,6333111,6333311,6333331,6333333,6611111,6621111,6622111,6622211,6622221,6622222,6631111,6633111,6633311,6633331,6633333,6661111,6662111,6662211,6662221,6662222,6663111,6663311,6663331,6663333,6666111,6666211,6666221,6666222,6666311,6666331,6666333,6666611,6666621,6666622,6666631,6666633,6666661,6666662,6666663,6666666,7111111,7711111,7771111,7777111,7777711,7777771,7777777,8111111,8211111,8221111,8222111,8222211,8222221,8222222,8411111,8421111,8422111,8422211,8422221,8422222,8441111,8442111,8442211,8442221,8442222,8444111,8444211,8444221,8444222,8444411,8444421,8444422,8444441,8444442,8444444,8811111,8821111,8822111,8822211,8822221,8822222,8841111,8842111,8842211,8842221,8842222,8844111,8844211,8844221,8844222,8844411,8844421,8844422,8844441,8844442,8844444,8881111,8882111,8882211,8882221,8882222,8884111,8884211,8884221,8884222,8884411,8884421,8884422,8884441,8884442,8884444,8888111,8888211,8888221,8888222,8888411,8888421,8888422,8888441,8888442,8888444,8888811,8888821,8888822,8888841,8888842,8888844,8888881,8888882,8888884,8888888,9111111,9311111,9331111,9333111,9333311,9333331,9333333,9911111,9931111,9933111,9933311,9933331,9933333,9991111,9993111,9993311,9993331,9993333,9999111,9999311,9999331,9999333,9999911,9999931,9999933,9999991,9999993,9999999,11111111,21111111,22111111,22211111,22221111,22222111,22222211,22222221,22222222,31111111,33111111,33311111,33331111,33333111,33333311,33333331,33333333,41111111,42111111,42211111,42221111,42222111,42222211,42222221,42222222,44111111,44211111,44221111,44222111,44222211,44222221,44222222,44411111,44421111,44422111,44422211,44422221,44422222,44441111,44442111,44442211,44442221,44442222,44444111,44444211,44444221,44444222,44444411,44444421,44444422,44444441,44444442,44444444,51111111,55111111,55511111,55551111,55555111,55555511,55555551,55555555,61111111,62111111,62211111,62221111,62222111,62222211,62222221,62222222,63111111,63311111,63331111,63333111,63333311,63333331,63333333,66111111,66211111,66221111,66222111,66222211,66222221,66222222,66311111,66331111,66333111,66333311,66333331,66333333,66611111,66621111,66622111,66622211,66622221,66622222,66631111,66633111,66633311,66633331,66633333,66661111,66662111,66662211,66662221,66662222,66663111,66663311,66663331,66663333,66666111,66666211,66666221,66666222,66666311,66666331,66666333,66666611,66666621,66666622,66666631,66666633,66666661,66666662,66666663,66666666,71111111,77111111,77711111,77771111,77777111,77777711,77777771,77777777,81111111,82111111,82211111,82221111,82222111,82222211,82222221,82222222,84111111,84211111,84221111,84222111,84222211,84222221,84222222,84411111,84421111,84422111,84422211,84422221,84422222,84441111,84442111,84442211,84442221,84442222,84444111,84444211,84444221,84444222,84444411,84444421,84444422,84444441,84444442,84444444,88111111,88211111,88221111,88222111,88222211,88222221,88222222,88411111,88421111,88422111,88422211,88422221,88422222,88441111,88442111,88442211,88442221,88442222,88444111,88444211,88444221,88444222,88444411,88444421,88444422,88444441,88444442,88444444,88811111,88821111,88822111,88822211,88822221,88822222,88841111,88842111,88842211,88842221,88842222,88844111,88844211,88844221,88844222,88844411,88844421,88844422,88844441,88844442,88844444,88881111,88882111,88882211,88882221,88882222,88884111,88884211,88884221,88884222,88884411,88884421,88884422,88884441,88884442,88884444,88888111,88888211,88888221,88888222,88888411,88888421,88888422,88888441,88888442,88888444,88888811,88888821,88888822,88888841,88888842,88888844,88888881,88888882,88888884,88888888,91111111,93111111,93311111,93331111,93333111,93333311,93333331,93333333,99111111,99311111,99331111,99333111,99333311,99333331,99333333,99911111,99931111,99933111,99933311,99933331,99933333,99991111,99993111,99993311,99993331,99993333,99999111,99999311,99999331,99999333,99999911,99999931,99999933,99999991,99999993,99999999,111111111,211111111,221111111,222111111,222211111,222221111,222222111,222222211,222222221,222222222,311111111,331111111,333111111,333311111,333331111,333333111,333333311,333333331,333333333,411111111,421111111,422111111,422211111,422221111,422222111,422222211,422222221,422222222,441111111,442111111,442211111,442221111,442222111,442222211,442222221,442222222,444111111,444211111,444221111,444222111,444222211,444222221,444222222,444411111,444421111,444422111,444422211,444422221,444422222,444441111,444442111,444442211,444442221,444442222,444444111,444444211,444444221,444444222,444444411,444444421,444444422,444444441,444444442,444444444,511111111,551111111,555111111,555511111,555551111,555555111,555555511,555555551,555555555,611111111,621111111,622111111,622211111,622221111,622222111,622222211,622222221,622222222,631111111,633111111,633311111,633331111,633333111,633333311,633333331,633333333,661111111,662111111,662211111,662221111,662222111,662222211,662222221,662222222,663111111,663311111,663331111,663333111,663333311,663333331,663333333,666111111,666211111,666221111,666222111,666222211,666222221,666222222,666311111,666331111,666333111,666333311,666333331,666333333,666611111,666621111,666622111,666622211,666622221,666622222,666631111,666633111,666633311,666633331,666633333,666661111,666662111,666662211,666662221,666662222,666663111,666663311,666663331,666663333,666666111,666666211,666666221,666666222,666666311,666666331,666666333,666666611,666666621,666666622,666666631,666666633,666666661,666666662,666666663,666666666,711111111,771111111,777111111,777711111,777771111,777777111,777777711,777777771,777777777,811111111,821111111,822111111,822211111,822221111,822222111,822222211,822222221,822222222,841111111,842111111,842211111,842221111,842222111,842222211,842222221,842222222,844111111,844211111,844221111,844222111,844222211,844222221,844222222,844411111,844421111,844422111,844422211,844422221,844422222,844441111,844442111,844442211,844442221,844442222,844444111,844444211,844444221,844444222,844444411,844444421,844444422,844444441,844444442,844444444,881111111,882111111,882211111,882221111,882222111,882222211,882222221,882222222,884111111,884211111,884221111,884222111,884222211,884222221,884222222,884411111,884421111,884422111,884422211,884422221,884422222,884441111,884442111,884442211,884442221,884442222,884444111,884444211,884444221,884444222,884444411,884444421,884444422,884444441,884444442,884444444,888111111,888211111,888221111,888222111,888222211,888222221,888222222,888411111,888421111,888422111,888422211,888422221,888422222,888441111,888442111,888442211,888442221,888442222,888444111,888444211,888444221,888444222,888444411,888444421,888444422,888444441,888444442,888444444,888811111,888821111,888822111,888822211,888822221,888822222,888841111,888842111,888842211,888842221,888842222,888844111,888844211,888844221,888844222,888844411,888844421,888844422,888844441,888844442,888844444,888881111,888882111,888882211,888882221,888882222,888884111,888884211,888884221,888884222,888884411,888884421,888884422,888884441,888884442,888884444,888888111,888888211,888888221,888888222,888888411,888888421,888888422,888888441,888888442,888888444,888888811,888888821,888888822,888888841,888888842,888888844,888888881,888888882,888888884,888888888,911111111,931111111,933111111,933311111,933331111,933333111,933333311,933333331,933333333,991111111,993111111,993311111,993331111,993333111,993333311,993333331,993333333,999111111,999311111,999331111,999333111,999333311,999333331,999333333,999911111,999931111,999933111,999933311,999933331,999933333,999991111,999993111,999993311,999993331,999993333,999999111,999999311,999999331,999999333,999999911,999999931,999999933,999999991,999999993,999999999};
    int t;
    scanf("%d",&t);
    while(t--)
    {
        int l,r;


        scanf("%d%d",&l,&r);
        int num1=0,num2=0;


        int out=0;
        for(int i=0;i<1300;i++)
        {
            if(l<=ans[i]&&r>=ans[i])out++;
        }
        printf("%d\n",out);
    }
}


 
时频分析之STFT:短时傅里叶变换的原理与代码实现(非调用Matlab API) STFT function [STFT, f, t] = mystft(x, win, hop, nfft, fs) % function: [STFT, f, t] = stft(x, win, hop, nfft, fs) % % Input: % x - signal in the time domain % win - analysis window function % hop - hop size % nfft - numb 阅读详情

相关推荐

程序员的自我修养

一个好的程序员的自我修养需要从不同角度出发,工作能力是一个方面,对自身的定位和了解也是一个方面,程序员的工作能力修养包括需求理解、功能设计、沟通确认、代码规范、成果验证、代码重构优化等,通过自我剖析来对自身进行定位并了解自身的优缺点,如去除劣根性、端正意识形态与态度、提升自己的核心竞争力等。 自我剖析 一个成功的人,必须要先了解自己,只有了解自己是什么样的人,了解自身有哪些优缺点,了解自己更合适做什么工作,知道自己做什么才能发挥出自身的优势,这样才能使自己在工作中发光发热,在职业生涯的道路上走的更远。

数通畅联 1674

BC#31.1002beautiful number——数位DP/暴力

http://bestcoder.hdu.edu.cn/contests/contest_chineseproblem.php?cid=569&pid=1002先离线暴力出1~1e9中所有的美丽数,总共1299个#include<iostream> #include<cstring> #include<cstdio> const int maxn=2000; using namespace std;

fsdcyr 9446

摄像头visio_最全面弱电智能VISIO图标集(百个),高大上方案就靠这个了

原标题:最全面弱电智能VISIO图标集(百个),高大上方案就靠这个了不会用Visio,Visio画拓扑画的很丑,怎么办?本期sin66小编免费分享一份最全面的弱电智能VISIO图标集(百个)给大家,以后画拓扑、做方案,直接高大上起来!需要本期资料直接看文末!!接下来我们一起看一下这些Visio图标大全:我们从下图可以看出前端设备主要是由枪机,筒机,无线摄像头,半球,球机,USB摄像头等构成,对于绘...

weixin_39644915的博客 1万+

任我发财663311conm_663311.com域名信息查询

Domain Name: 663311.COMRegistry Domain ID: 1736029272_DOMAIN_COM-VRSNRegistrar WHOIS Server: whois.godaddy.comRegistrar URL: http://www.godaddy.comUpdated Date: 2020-12-14T06:18:09ZCreation Date: 2012...

weixin_36200490的博客 5865

ZYNQ开发(2)在Linux系统层上PL-PS通过AXI-DMA传输数据详细步骤及注意事项

参考的网络资料 https://github.com/bperez77/xilinx_axidma/tree/master https://gitlab.gnome.org/HosseinBeheshti/UlteraZed7EV/-/tree/master/petalinux/xilinx_axidma https://www.icode9.com/content-3-925319.html https://blog.csdn.net/weixin_38218267/article/details/1

aizaiyueye的专栏 3448

RWEQ土壤风蚀模型的估算与变化归因分析

本次以介绍RWEQ模型的基本原理及数据需求,再结合案例讲解RWEQ模型中区域地理空间数据库构建的方法和各个参量提取的原理与方法,最后结合典型案例进行综合讲解风蚀模数估算、制图及归因分析。空间分析与制图:提取分析、局部分析、邻域分析、区域分析、插值分析、平滑处理、像元提取、采样与重采样。以某实际应用为案例,掌握RWEQ模型进行当地土壤风蚀量空间分布分析整体流程。地图服务器、在线地图、范围指示器、格网、表格、基础地图服务使用规则介绍。掌握土壤风蚀模型的原理、优势点及因子组成。

2301_77413856的博客 1193

1128d_1128d.com域名信息查询

Domain Name: 1128D.COMRegistry Domain ID: 2210701918_DOMAIN_COM-VRSNRegistrar WHOIS Server: whois.godaddy.comRegistrar URL: http://www.godaddy.comUpdated Date: 2019-12-24T07:18:47ZCreation Date: 2018-...

weixin_33265716的博客 2216

手把手教你用高频注入法辨识永磁同步电机电感参数(附MATLAB仿真)

本文详细介绍了高频注入法在永磁同步电机电感参数辨识中的工程实践与MATLAB仿真指南。通过高频信号注入法,无需拆解电机即可在线精确测量Ld和Lq参数,适用于电动汽车驱动和工业伺服等高精度控制场景。文章包含信号设计、硬件实现、解调算法及完整MATLAB仿真模型构建,帮助工程师快速掌握这一关键技术。

orange的博客 292

针对小数据集和大数据集计算出漂亮数(谷歌面试题)

1.小数据集: 这里表示小于2^31-1的正整数。 2.大数据集: 大于2^31-1的正整数。 3.为何分出大数据集和小数据集: 因为解决小数据集的算法当遇到大数量数据时,往往无法解决 4.何为漂亮数: 输入的数被漂亮数求的余每一位都为1 以下为分别解小数据集和大数据集的java代码: 1.解小数据集 package com.zr.demo; import java.util.Scanner; ...

liangruilz的博客 590

避坑指南:ANSYS流固耦合计算中System Coupling数据传递设置与常见报错解决

本文深入解析ANSYS Workbench中System Coupling模块在双向流固耦合(FSI)计算中的应用,详细讲解数据传递机制、典型报错解决方案及高阶调试技巧。通过实际案例展示如何优化耦合步长、处理大变形问题,并提升并行计算效率,帮助工程师有效规避常见技术陷阱。

weixin_29213525的博客 723

MDIO接口协议与其详解——单片机

在单片机领域,通过MDIO接口可以与外部设备进行通信,实现对设备的控制和数据的读写。通过本文的介绍,你可以了解到MDIO接口协议的原理和使用方法,并参考源代码示例进行实际的开发和应用。具体的初始化方法与单片机的型号和开发环境有关,可以参考相应的单片机手册和开发工具的文档。(1)发送读取命令:向MDIO线发送读取命令,通常是发送一个特定的控制字节,用于指示要读取的寄存器地址。(1)发送写入命令:向MDIO线发送写入命令,通常是发送一个特定的控制字节,用于指示要写入的寄存器地址。二、MDIO接口协议使用方法。

web_class282的博客 2623

Problem B. Beautiful Numbers Google APAC 2017 University Test Round E

这一题要求all of its digits become 1,所以在base B下,假设N可以表示成p位数,这个数的值就是一个等差数列,因为N是long long范围,p最多为64。 记,因为B>1,给定p时,求导可以得出f(B)是单调增的。因此在给定p时,可以通过二分查找得出B的值。 这一题小数据我在二分的时候用除法比较abs(f(B)) 小数据代码如下。 #include #in

TimeForMiracles 797

170、电机控制中的温升测试

本文以一次IGBT炸管事故为切入点,深入剖析电机控制中温升测试的实质:不仅是温度测量,更是对铜损、铁损、散热效率等热管理问题的系统验证。作者强调测试前热电偶布置、环境记录、预运行的重要性,提出实时监控电流谐波、绕组电阻、散热梯度等关键参数,并通过损耗分离与冷却系统实测,揭示真实热源。结合温升曲线异常分析与经验建议,强调留余量、仿真结合实测、关注瞬态工况等实践要点,警示温升测试是保障可靠性与安全性的核心环节。

2401_88858637的博客 47

hdu(5179):beautiful number

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5179   这是BestCode上的题目,但是比赛时,只有思路,却写不出来,当然,对于我来讲,能够知道用Dp来做这种思路就是一大满足了。 赛后看题解,说是最多有1299个解,可以先打印出来。擦,当时我已经推出最多有1299个解了,可咋就没想到打印呢,反正解又不多!!   代码及详解:  

catch_catch的专栏 530

TMS_WebGMaps_1.9.8.0_Full_Source

TMS_WebGMaps_1.9.8.0_Full_Source 全源码 delphi cbuilder

大中型超市收银系统(可直接运行)

光步前台收银系统系统功能:商品销售、商品退货、挂单、收银员权限、会员销售、单品取消、整单取消、商品查询、脱机销售、脱机数据上传,基本资料下载,开钱箱、小票打印、收款结算,支持多币种付款方式(现金、储值卡、礼券、微信等),支持多种促销。运行环境:.net 4.0登陆信息用户名:1001 密码:123456内置商品信息,商品编码可输入00001000 - 00010000,测试效果相关功能键F5 结算 F9挂单 F11商品查询 F8退货 Insert单品取消 Del整单取消 F12开钱箱F2 会员 Ctrl+Z退出系统 Home 锁屏 相关源码待公开

hdu 5179-beautiful number

题目:给定一个区间的两个区间端点l和r,问在l和r之间有多少满足下列情况的数字---这个数字应该满足前一位是后一位的倍数。 分析:这是一个经典的数位DP的题目,我们可以把区间求和转化成两个区间的减法,即S[1,r]-S[1,l-1]就是我们求得的答案。          那么问题就转化成了求1-n之间满足情况的数的个数,那么我们就要使用dp[i][j]求得数字长度为i,首数字为j的满足情况的数

浮躁的人,终究一事无成! 934

jre9下载 jdk9

(Java SE Runtime Environment 9.0) 9.0u175 官方最新版 【x86|x64】

HDU5179 beautiful number 数位DP

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5179 题目大意:找出[l,r]中高位数字可以整除低位且不小于低位数字的数的个数。 实现代码如下: #include #include #include #include using namespace std; int dp[25][25][3]; int bi

AC_Gibson的专栏 632

复分析 阿尔福斯(Ahlfors) 第三版答案 英文

答案分为十章,有部分习题没有答案,全英文复分析阿尔福斯(Ahlfors) 第三版答案

HDU 5179 beautiful number

传送门 数位dp。(要考虑前导0,类似还有POJ 3252) 定义一种数,要求在其十进制数位上,较高位都>=较低位,且较高位%较低位都是0(较高位都能被较低位整除)。问你[L,R]内有多少个这种数。 需要注意几点。 dp第二维记录第i+1位数字,整除关系可以传递。中途判断。 默认之前位都已满足要求,所以只要当前位能整除第i+1位,就可整除前面任意一位。 满足要求的数中,只有一个数可以含有0...

Crossing over 256

HDU 5179 beautiful number 离线处理

传送门:http://acm.hdu.edu.cn/showproblem.php?pid=5179 beautiful number Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 176    Accepted

阑珊记忆 6900

【HDOJ】5179 beautiful number

DFS。 1 /* 5179 */ 2 #include <iostream> 3 #include <algorithm> 4 #include <map> 5 #include <cstdio> 6 #include <cstring> 7 using namespace std; 8 9 #...

weixin_34128839的博客 127

hdu5179---beautiful number

Problem Description Let A=∑ni=1ai∗10n−i(1≤ai≤9)(n is the number of A’s digits). We call A as “beautiful number” if and only if a[i]≥a[i+1] when 1≤i/****************************************************

Alex 1458

HDU5179 beautiful number

题意 对于一个数,如果他的每一位都是前一位的因数,那么他就是beautiful number,如931 这个数每一位1<=ai<=9,1<=l,r<=1e9 题解 这道题还是比较简单的,想到DP状态f[s][pre],但是前导零也有影响,因为原题要求每一位不为0,所以加一维前导零即可 #include<bits/stdc++.h> using...

weixin_30713953的博客 137

hdu 5179 beautiful number【数位dp】

beautiful number Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 503    Accepted Submission(s): 304 Problem Description Let A=∑ni=1ai

mengxiang000000 932

HDOJ 5179 beautiful number

beautiful number Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 707    Accepted Submission(s): 451 Problem Description Let A=∑ni=1ai

Dust_heart的博客 436

hdu5179 beautiful number

hdu5179 beautiful number

alpc_wt的专栏 1307

hdu-5179 beautiful number

beautiful numberTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 951    Accepted Submission(s): 610Problem DescriptionLet A=∑ni=1ai∗10n−i(1≤ai≤9)...

qq_37064135的博客 211

HDU 5179 beautiful number 数位DP(水)

HDU 5179 题意:x={a[1]a[2]a[2]..a[n]},a[1]为高位.  定义一个数x合法,当a[i]>=a[i+1] && a[i]%a[j]==0(1 L,R 假如最高位为y,a[1]=y 则后面所有的数都为a[1]的因子. 其实只要记录前面一个数是多少 后面一个数只要为它的因子即可. 数位DP套路:f[pos][pre] 还需要pos位 前一位为pre

noone0的博客 315
上一篇: 4277 USACO ORZ
下一篇: 1387 Decoding Morse Sequences
矢澤 年
博客等级 码龄10年 3粉丝 52原创
评论
成就一亿技术人!
拼手气红包6.0元
还能输入1000个字符
 
 条评论被折叠 查看
添加红包

请填写红包祝福语或标题

个

红包个数最小为10个

元

红包金额最低5元

当前余额3.43元 前往充值 >
需支付:10.00元
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付元
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值