浙江工商大学23调剂机试（扫雷游戏）

题解：需定义方向导数来遍历其周围的8个位置

#include<bits/stdc++.h>
using namespace std;

int main() {
    int n, m;
    cin >> n >> m;
    vector<vector<char>> grid(n, vector<char>(m));
    
    for (int i = 0; i < n; ++i) {
        for (int j = 0; j < m; ++j) {
            cin >> grid[i][j];
        }
    }
    
    vector<vector<char>> res(n, vector<char>(m));
    // 定义八个方向的偏移量
    int dx[] = {-1, -1, -1, 0, 0, 1, 1, 1};
    int dy[] = {-1, 0, 1, -1, 1, -1, 0, 1};
    
    for (int i = 0; i < n; ++i) {
        for (int j = 0; j < m; ++j) {
            if (grid[i][j] == '*') {
                res[i][j] = '*';
            } else {
                int count = 0;
                for (int k = 0; k < 8; ++k) {
                    int x = i + dx[k];
                    int y = j + dy[k];
                    if (x >= 0 && x < n && y >= 0 && y < m && grid[x][y] == '*') {
                        count++;
                    }
                }
                res[i][j] = '0' + count;
            }
        }
    }
    
    for (int i = 0; i < n; ++i) {
        for (int j = 0; j < m; ++j) {
            if (j > 0) cout << ' ';
            cout << res[i][j];
        }
        cout << endl;
    }
    
    return 0;
}