创建链表（一）

一，创建链表结构带有头节点的链表

/*************************************************************************
    > File Name: 111单链表.c
    > Author: songli
    > QQ: 2734030745
    > Mail: 15850774503@163.com
        > 优快云: http://my.youkuaiyun.com/Poisx
    > github: https://github.com/chensongpoixs
    > Created Time: Thu 24 Aug 2017 05:38:09 AM PDT
 ************************************************************************/

#include <stdio.h>
#include <stdlib.h>

struct LNode
{
    int data;
    struct LNode * next;
};

struct LNode *create(int n)
{
    int i;
    struct LNode *head, *p1, *p2 = NULL; //VS编译器中指针要初始化 gcc 编译器已经优化过了
    int a;
    head = NULL;  //头节点为NULL
    printf("Input the integers:\n");
    for (i = n; i > 0; --i)
    {
        //分配空间
        p1 = (struct LNode*)malloc(sizeof(struct LNode)); 
        //输入数据
        scanf("%d", &a);
        p1->data = a; //数据域赋值
        //指定头结点
        if (head == NULL)
        {
            head = p1;  //把p1 付给头结点
            p2 = p1;  //第一
        }
        else 
        {
            p2->next = p1;
            p2 = p1;
        }
    }
    p2->next = NULL;
    return head;
}

int main(int argc, char *argv[])
{
    int n;
    struct LNode *q;
    printf("Input the count of the nodes you want to creat:");
    scanf("%d", &n);
    q = create(n);
    printf("The result is :\n");
    while (q)
    {
        printf("%d ", q->data);
        q = q->next;
    }    

    return 0;
}

github的链接