a=[[30.707473754882812, 104.04808044433594], [30.707473754882812, 104.04533386230469], [30.707473754882812, 104.04258728027344], [30.707473754882812, 104.04670715332031], [30.711593627929688, 104.04258728027344], [30.711593627929688, 104.04808044433594], [30.710220336914062, 104.04670715332031], [30.707473754882812, 104.04396057128906], [30.708847045898438, 104.04533386230469], [30.710220336914062, 104.04396057128906], [30.708847045898438, 104.05082702636719], [30.710220336914062, 104.04121398925781], [30.708847045898438, 104.04258728027344], [30.710220336914062, 104.04258728027344], [30.708847045898438, 104.04121398925781], [30.710220336914062, 104.04945373535156], [30.707473754882812, 104.04945373535156], [30.711593627929688, 104.05082702636719], [30.711593627929688, 104.04945373535156], [30.710220336914062, 104.04533386230469], [30.711593627929688, 104.04670715332031], [30.710220336914062, 104.04808044433594], [30.707473754882812, 104.05082702636719], [30.711593627929688, 104.04121398925781], [30.707473754882812, 104.04121398925781], [30.711593627929688, 104.04533386230469], [30.708847045898438, 104.04396057128906], [30.711593627929688, 104.04396057128906], [30.710220336914062, 104.05082702636719], [30.708847045898438, 104.04670715332031], [30.708847045898438, 104.04945373535156], [30.708847045898438, 104.04808044433594]]
b=0.01
z={}
for i in range(len(a)):
z[str(a[i])]=b
print(z)
python列表与变量转换为字典
最新推荐文章于 2021-05-25 17:54:24 发布
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