IP Address

最新推荐文章于 2023-01-14 21:38:05 发布

原创最新推荐文章于 2023-01-14 21:38:05 发布 · 414 阅读

0 ·

CC 4.0 BY-SA版权

简单题专栏收录该内容

36 篇文章

订阅专栏

本文介绍了一种将32位二进制数转换为IPv4地址的方法，并提供了一个示例程序来展示如何通过分组并转换每组二进制数来实现这一转换。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

Description

Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are:

27	26	25	24	23	22	21	20
128	64	32	16	8	4	2	1

Input

The input will have a number N (1 <= N <= 9) in its first line representing the number of streams to convert. N lines will follow.

Output

The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.

Sample Input

4
00000000000000000000000000000000
00000011100000001111111111111111
11001011100001001110010110000000
01010000000100000000000000000001

Sample Output

0.0.0.0
3.128.255.255
203.132.229.128
80.16.0.1

#include <iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int main()  
{
    
    int T;  
    char s;
    scanf("%d",&T);
    while(T--)  
    {  
        int sum; 
	    int a[8]={128,64,32,16,8,4,2,1}; 
        for(int i=0;i<4;i++)  
        {  
            sum=0;  
            for(int j=0;j<8;j++)  
            {  
                cin>>s;  
                s-='0';  
                if(s) 
				sum+=a[j];  
            }  
            if(i!=0)
			 printf(".");
            printf("%d",sum);
        }
        printf("\n");
    }
    return 0;  
}