4.9作业

#!/bin/bash
read -p "输入一个数组" -a arr
read -p "输入一个key" a
found=0
for ((i=0;i<${#arr[*]};i++))
do
    if [ $a -eq ${arr[i]} ]
    then
        echo $a
        found=1
    fi
done
if [ $found -eq 0 ]            
then
    echo "无"
fi

read -p "输入一个数组" -a arr
read -p "输入一个key" a
found=0
for ((i=0;i<${#arr[*]};i++))
do
    if [ $a -eq ${arr[i]} ]
    then
        arr[i]=hehe
        found=1
    fi
done
if [ $found -eq 0 ]
then
    echo "无符合元素"
else
echo arr=${arr[@]}
fi                             

 read -p "输入一个数组" -a arr
 read -p "输入一个key" a
 found=0
 for ((i=0;i<${#arr[*]};i++))
 do
     if [ $a -eq ${arr[i]} ]
     then
         t=$i
 for ((e=$t;e<${#arr[*]}-1;e++))
 do
     ((arr[e]=arr[e+1]))
 done
 found=1
 fi
 done
 if [ $found -eq 0 ]
 then
     echo "无匹配数字"
 else
 arr[e]=
 echo arr=${arr[*]}
 fi                             

for i in `seq 1 1 3`
do
    read -p "请输入用户名" -s a
    echo
    read -p "请输入密码" -s b
    echo
    c=10000
    if [ $a = admin -a $b = 123 ]
    then
        select i in "账户余额" "取款" "存款" "退出"
        do
            case $i in
                "账户余额")
                    echo "账户余额 $c"
                    ;;
                "取款")
                    i=0
                    while [ $i -ne 1 ]
                    do
                        read -p "输入取款金额" s
                        if [ $s -gt $c ]
                        then
                            echo "账户余额不足，请重新输入"
                        else
                            echo "取款成功 剩余余额$((c-s))"
                            i=1
                        fi
                    done
                    ;;
                    "存款")
                        read -p "输入存款金额" d
                        if [ $s -eq 0 ]
                        then
                        echo "存款成功 余额$((c+d))"          
                    else
                        echo "存款成功 余额$((c-s+d))"
                        fi
                        ;;
                    "退出")
                        break
                        ;;
                        *)
                            echo error
                            ;;
                    esac
                done
    else
        if [ $i -lt 3 ]
        then
            echo 还有$((3-i))次机会
        else
            echo 账户被锁定
        fi
    fi
done