字符串驻留问题

最新推荐文章于 2024-08-08 09:06:02 发布

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本文通过一个C#示例代码深入探讨了字符串Intern池的工作原理，解释了如何利用object.ReferenceEquals方法来判断两个字符串是否引用相同对象，以及字符串连接操作如何影响Intern池。

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static void Main(string[] args)
        {
            string str1 = "ABCD1234";
            string str2 = "ABCD1234";
            string str3 = "ABCD";
            string str4 = "1234";
            string str5 = "ABCD" + "1234";
            string str6 = "ABCD" + str4;
            string str7 = str3 + str4;  
            Console.WriteLine("string str1 = \"ABCD1234\";"); 
            Console.WriteLine("string str2 = \"ABCD1234\";"); 
            Console.WriteLine("string str3 = \"ABCD\";"); 
            Console.WriteLine("string str4 = \"1234\";"); 
            Console.WriteLine("string str5 = \"ABCD\" + \"1234\";"); 
            Console.WriteLine("string str6 = \"ABCD\" + str4;"); 
            Console.WriteLine("string str7 = str3 + str4;"); 
            Console.WriteLine("\nobject.ReferenceEquals(str1, str2) = {0}", object.ReferenceEquals(str1, str2)); 
            Console.WriteLine("object.ReferenceEquals(str1, \"ABCD1234\") = {0}", object.ReferenceEquals(str1,"ABCD1234")); 
            Console.WriteLine("\nobject.ReferenceEquals(str1, str5) = {0}", object.ReferenceEquals(str1, str5)); 
            Console.WriteLine("object.ReferenceEquals(str1, str6) = {0}", object.ReferenceEquals(str1, str6)); 
            Console.WriteLine("object.ReferenceEquals(str1, str7) = {0}", object.ReferenceEquals(str1, str7)); 
            Console.WriteLine("\nobject.ReferenceEquals(str1, string.Intern(str6)) = {0}", object.ReferenceEquals(str1, string.Intern(str6))); 
            Console.WriteLine("object.ReferenceEquals(str1, string.Intern(str7)) = {0}", object.ReferenceEquals(str1, string.Intern(str7)));
            Console.ReadKey();
        }

输出结果：
object.ReferenceEquals(str1, str2) = True
object.ReferenceEquals(str1, "ABCD1234") = True

object.ReferenceEquals(str1, str5) = True
object.ReferenceEquals(str1, str6) = False
object.ReferenceEquals(str1, str7) = False

object.ReferenceEquals(str1, string.Intern(str6)) = True
object.ReferenceEquals(str1, string.Intern(str7)) = True

intern pool（驻留池），对于字符串新建的，新建时要到intern pool搜索，看是否存在与此字符串内容相同的字符串，如果有这返回存在intern pool中字符串的引用，否则将要新建的字符串加入intern pool，并返回引用。