[Leetcode]628. Maximum Product of Three Numbers

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Given an integer array, find three numbers whose product is maximum and output the maximum product.

Example 1:

Input: [1,2,3]
Output: 6

 

Example 2:

Input: [1,2,3,4]
Output: 24

 

Note:

1. The length of the given array will be in range [3,104] and all elements are in the range [-1000, 1000].
2. Multiplication of any three numbers in the input won't exceed the range of 32-bit signed integer.

 

思路：乘积最大，则肯定是寻找三个绝对值最大的数相乘。所以先把数组排序，这样数值最大的数为最后三个。第一反应应该会认为

数组末尾三个数乘积就是答案了。但是数组里可能还会有负数，如果数组最开头两个数是负数，且绝对值很大，则答案可能是头两个数

和数组末尾的那个数相乘；

 

1 class Solution {
2     public int maximumProduct(int[] nums) {
3         Arrays.sort(nums);
4         int p = nums.length;
5         int product1 = nums[p-1]*nums[p-2]*nums[p-3];
6         int product2 = nums[p-1]*nums[0]*nums[1];
7         return product1>product2?product1:product2;
8     }
9 }

 

转载于:https://www.cnblogs.com/David-Lin/p/7740054.html