#include<cstdio>
using namespace std;
typedef long long ll;
const int M=9901;
ll p[100],k[100];
ll power(ll n,ll m){
ll sq=1;
while(m){
if(m&1)sq=sq*n%M;
m>>=1;
n=n*n%M;
}
return sq;
}
ll sum(ll n,ll m){
if(m==0)return 1;
if(m&1)return sum(n,m/2)*(1+power(n%M,m/2+1))%M;
return (sum(n,m/2-1)*(1+power(n%M,m/2+1))+power(n%M,m/2))%M;
}
int main(){
ll a,b,i,l=0,ans=1;
scanf("%lld%lld",&a,&b);
for(i=2;i*i<=a;){
if(a%i==0){
p[++l]=i;
while(a%i==0){
k[l]++;
a/=i;
}
}
if(i==2)i++;
else i+=2;
}
if(a!=1){
p[++l]=a;
k[l]=1;
}
for(i=1;i<=l;i++)
ans=ans*sum(p[i],k[i]*b)%M;
if(a!=0)printf("%lld\n",ans);
else puts("0");
return 0;
}
POJ 1845 Sumdiv
最新推荐文章于 2020-05-01 21:43:20 发布