CF#807 A. Is it rated?（水题）

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本文介绍了一个简单的算法问题，旨在判断一场编程比赛是否为评级赛事。通过输入赛前赛后选手的评分变化，结合特定条件，输出赛事评级状态。文章提供了解决方案的代码实现。

Is it rated?

Here it is. The Ultimate Question of Competitive Programming, Codeforces, and Everything. And you are here to answer it.

Another Codeforces round has been conducted. No two participants have the same number of points. For each participant, from the top to the bottom of the standings, their rating before and after the round is known.

It's known that if at least one participant's rating has changed, then the round was rated for sure.

It's also known that if the round was rated and a participant with lower rating took a better place in the standings than a participant with higher rating, then at least one round participant's rating has changed.

In this problem, you should not make any other assumptions about the rating system.

Determine if the current round is rated, unrated, or it's impossible to determine whether it is rated of not.

Input

The first line contains a single integer n (2 ≤ n ≤ 1000) — the number of round participants.

Each of the next n lines contains two integers ai and bi (1 ≤ ai, bi ≤ 4126) — the rating of the i-th participant before and after the round, respectively. The participants are listed in order from the top to the bottom of the standings.

Output

If the round is rated for sure, print "rated". If the round is unrated for sure, print "unrated". If it's impossible to determine whether the round is rated or not, print "maybe".

Examples

input
6
3060 3060
2194 2194
2876 2903
2624 2624
3007 2991
2884 2884

output
rated

input
4
1500 1500
1300 1300
1200 1200
1400 1400

output
unrated

input
5
3123 3123
2777 2777
2246 2246
2246 2246
1699 1699

output
maybe

Note

In the first example, the ratings of the participants in the third and fifth places have changed, therefore, the round was rated.

In the second example, no one's rating has changed, but the participant in the second place has lower rating than the participant in the fourth place. Therefore, if the round was rated, someone's rating would've changed for sure.

In the third example, no one's rating has changed, and the participants took places in non-increasing order of their rating. Therefore, it's impossible to determine whether the round is rated or not.

题目不难，就是读题恶心，要求是a[ i ] , b[ i ]若不相等，输出rated，当a[ i ] = b[ i ] 时，a1 ~ an若不是单调递减的，输出unrated，否则输出maybe。

#include<bits/stdc++.h>
using namespace std;

int n;
int a[1001], b[1001];

int main()
{
    while(scanf("%d", &n) == 1)
    {
        int flag = 0;
        for(int i = 0; i < n; i++)
        {
            scanf("%d%d", &a[i], &b[i]);
            if(a[i] != b[i]) flag = 1;
        }
        for(int i = 1; i < n; i++)
        {
            if(!flag && a[i] > a[i-1])
                flag = 2;
        }
        if(!flag) printf("maybe\n");
        else if(flag == 1) printf("rated\n");
        else printf("unrated\n");
    }
}