hdu 5916 Harmonic Value Description 最大公约数

Harmonic Value Description

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 929    Accepted Submission(s): 544
Special Judge


Problem Description
The harmonic value of the permutation p1,p2,pn is
i=1n1gcd(pi.pi+1)

Mr. Frog is wondering about the permutation whose harmonic value is the strictly k-th smallest among all the permutations of [n].
 

Input
The first line contains only one integer T ( 1T100 ), which indicates the number of test cases.

For each test case, there is only one line describing the given integers n and k ( 12kn10000 ).
 

Output
For each test case, output one line “Case #x: p1 p2  pn ”, where x is the case number (starting from 1) and p1 p2  pn is the answer.
 

Sample Input
  
  
2 4 1 4 2
 

Sample Output
  
  
Case #1: 4 1 3 2 Case #2: 2 4 1 3
 

Source

2016中国大学生程序设计竞赛(长春)-重现赛  

// CcpcTraining.cpp: 定义控制台应用程序的入口点。
//#include "stdafx.h"
#include<iostream>
using namespace std;

int main() {
    int n, k, test;
    cin >> test;
    for (int cases = 1; cases <= test; cases++) {
        cin >> n >> k;
        cout << "Case #" << cases << ":";
        cout << " " << 2 * k << " " << k;
        for (int i = k + 1; i <= 2 * k - 1; i++) {
            cout << " " << i;
        }
        for (int i = 2 * k + 1; i <= n; i++) {
            cout << " " << i;
        }
        for (int i = 1; i <= k - 1; i++) {
            cout << " " << i;
        }
        cout << endl;
    }
    return 0;
}



评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值