校验时间(hh:mm)

思路很简单，格式化时间。

public static boolean checkHHMM(String time) {
        SimpleDateFormat dateFormat = new SimpleDateFormat("hh:mm");
        try {
            @SuppressWarnings("unused")
            Date t = dateFormat.parse(time);
        } catch (Exception ex) {
            return false;
        }
        return true;
    }

public static boolean checkTime(String time) {
        if (checkHHMM(time)) {
            String[] temp = time.split(":");
            if ((temp[0].length() == 2 || temp[0].length() == 1) && temp[1].length() == 2) {
                int h = 0;
                int m = 0;
                try {
                    h = Integer.parseInt(temp[0]);
                    m = Integer.parseInt(temp[1]);
                    if (!Objects.equals(m, 30) && !Objects.equals(m, 00)) {
                        throw new IllegalArgumentException("请输入正确的时间范围，时间粒度为30min-" + time);
                    }
                } catch (NumberFormatException e) {
                    return false;
                }
                if (h >= 0 && h <= 24 && m <= 60 && m >= 0) {
                    return true;
                }
            }
        }
        return false;
    }