表:course

score

student

teacher

代码段
SELECT student.SId AS 学号,student.Sname AS 姓名,student.Sage AS 年龄,student.Ssex AS 性别
FROM student
WHERE student.SId NOT IN
(SELECT score.SId
FROM score
GROUP BY score.SId
HAVING COUNT(score.CId)=(SELECT COUNT(course.CId) FROM course)
)
本文介绍了一个SQL查询,它从student表中选择那些未参与所有课程的学生,通过不在score表中学生ID的计数等于course表中课程数量的条件实现。
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