斐波那契数列-C语言实现

#include <stdio.h>
#include <stdlib.h>

int main()
{
    int n = 0;
    int i = 0;
    int count = 0;
    int *fi = NULL;
    printf("请输入年数：\n");
    scanf("%d", &n);
    fi = (int *)(malloc(sizeof(int)*n));
    fi[0] = 1;
    fi[1] = 1;
    for(i=2;i<n;i++)
    {
        fi[i] = fi[i-1]+fi[i-2];
    }
    printf("输出如下：\n");
    for(i=0;i<n;i++)
    {
        count++;
        printf("%8d", fi[i]);
        if(5==count)
        {
            putchar('\n');
            count = 0;
        }
    }
    putchar('\n');

    free(fi);
    return 0;
}