719 - 计算最大值

2017.10.24

当遍历到s的第i个字符时 d[i] = max(i*d[i-1], i+ d[i-1])

public class Solution {
    /*
     * @param : the given string
     * @return: the maximum value
     */
 	public int calcMaxValue(String str) {
        // write your code here
		if(str.length() == 0){
			return 0;
		}
		if(str.length() == 1){
			return Integer.valueOf(str);
		}
		int a = Integer.valueOf(str.substring(0,1));
		int b = Integer.valueOf(str.substring(1,2));
		int res = Math.max(a+b, b*a);
		if(str.length() == 2){
			return res;
		}
		for(int i = 2; i < str.length(); i++){
		    int tmp = Integer.valueOf(str.substring(i,i+1));
			//System.out.print("tmp = " + tmp + ";旧res = " + res);
			res = Math.max(tmp+res, tmp*res);
			//System.out.println(";新res = " + res);
		}
		return res;
    }
};