Hdu5804 Price List

opencv简单小项目 OpenCV(Open Source Computer Vision Library)是一个开源的计算机视觉和机器学习软件库,它提供了大量的图像和视频处理功能。要开始一个OpenCV项目,你需要安装OpenCV库,这通常可以通过Python的pip包管理器完成。替换为你要加载的图像的实际路径。这个例子展示了OpenCV项目的基本结构,你可以在此基础上添加更多的图像处理功能。如果你需要更详细的指导或代码示例,请告诉我你的具体需求。 阅读详情

Problem Description
There are n shops numbered with successive integers from 1 to n in Byteland. Every shop sells only one kind of goods, and the price of the i -th shop's goods is vi .
Every day, Byteasar will purchase some goods. He will buy at most one piece of goods from each shop. Of course, he can also choose to buy nothing. Back home, Byteasar will calculate the total amount of money he has costed that day and write it down on his account book.
However, due to Byteasar's poor math, he may calculate a wrong number. Byteasar would not mind if he wrote down a smaller number, because it seems that he hadn't used too much money.
Please write a program to help Byteasar judge whether each number is sure to be strictly larger than the actual value.
Input
The first line of the input contains an integer T (1≤T≤10) , denoting the number of test cases.
In each test case, the first line of the input contains two integers n,m (1≤n,m≤100000) , denoting the number of shops and the number of records on Byteasar's account book.
The second line of the input contains n integers v1,v2,...,vn (1≤vi≤100000) , denoting the price of the i -th shop's goods.
Each of the next m lines contains an integer q (0≤q≤1018) , denoting each number on Byteasar's account book.
Output
For each test case, print a line with m characters. If the i -th number is sure to be strictly larger than the actual value, then the i -th character should be '1'. Otherwise, it should be '0'.
Sample Input
  
1 3 3 2 5 4 1 7 10000
Sample Output
  
001
Source
Recommend
wange2014

当给定值超过所有数总和时,一定是不可能的,否则难以判断。


#include <iostream>
#include <cstdio>
#include <map>
#include <set>
#include <vector>
#include <queue>
#include <stack>
#include <cmath>
#include <algorithm>
#include <cstring>
#include <string>
using namespace std;
#define INF 0x3f3f3f3f
typedef long long LL;


int main()
{
    int t;
    int n,m,a;
    char c[100005];
    LL sum,b;
    scanf("%d",&t);
    while(t--){
        scanf("%d%d",&n,&m);
        sum=0;
        while(n--){
            scanf("%d",&a);
            sum+=a;
        }
        for(int i=0;i<m;i++){
            scanf("%lld",&b);
            if(b>sum){
                c[i]='1';
            }else{
                c[i]='0';
            }
        }
        for(int i=0;i<m;i++){
            printf("%c",c[i]);
        }
        printf("\n");
    }
    return 0;
}


【图像超分】论文复现:Pytorch实现SRCNN!保姆级复现教程!提供完整代码和最优权重模型(x2、x3、x4)!科研级论文曲线图!计算平均PSNR和SSIM!代码Windows和Linux都可用! 由于很多同学反应没用过jupyter notebook,更习惯用pycharm项目的形式跑代码。于是,本文将用pycharm项目的形式,重新复现SRCNN!【图像超分】论文复现:新手入门!Pytorch实现SRCNN,数据预处理、模型训练、测试、评估全流程详解,注释详细,简单修改就可以训练你自己的图像数据,有训练好的模型下载地址,随取随用。 阅读详情

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Problem Description There are n shops numbered with successive integers from 1 to n in Byteland. Every shop sells only one kind of goods, and the price of the i-th shop's goods is vi. Ever

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nn.output = 'softmax'; % use softmax outputopts.numepochs = 5; % Number of full sweeps through dataopts.batchsize = 1000; % Take a mean gradient step over this many samplesopts.plot = 1; % enable plottingnn = nntrain(nn, tx, ty, opts, vx, vy); % nntrain takes validation set as last two arguments (optionally)[er, bad] = nntest(nn, test_x, test_y);assert(er < 0.1, 'Too big error');```[![Bitdeli Badge](https://d2weczhvl823v0.cloudfront.net/rasmusbergpalm/deeplearntoolbox/trend.png)](https://bitdeli.com/free "Bitdeli Badge")

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HDU 5804 Price List (简单题)

题目链接 直接计算即可#include<cstdio> #include<algorithm> #include<iostream> #include<cstring> #include<string> #include<cmath> #include<map> #include<set> #include<cstdlib> #include<vector> using namespace std

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