SQL将一列转换成一行，并将这一行形成新的列

最新推荐文章于 2025-06-07 21:10:46 发布

原创最新推荐文章于 2025-06-07 21:10:46 发布 · 5.4k 阅读

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#行转列 #一行转一列

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本文介绍如何使用SQL将一列数据转换为多列，通过PIVOT操作实现，同时展示了C#后台如何处理数据，将一列转换成以逗号分隔的字符串。

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查询出来要转换的数据

SELECT name FROM dbo.base_pay_type WHERE is_enabled = 1

数据如图：

2.将查询到的数据转换成行，以逗号隔开，以【】包裹

SELECT STUFF((SELECT  '[' + name + '],'  
FROM(SELECT name FROM dbo.base_pay_type WHERE is_enabled = 1) a  FOR  XML PATH('')  ), 1,0, '') AS Name

数据如图：

3，去掉最后一个逗号

SELECT LEFT(a.Name,LEN(a.Name)-1) AS Name FROM (SELECT STUFF((SELECT  '[' + name + '],'  
FROM(SELECT name FROM dbo.base_pay_type WHERE is_enabled = 1) a  FOR  XML PATH('')  ), 1,0, '') AS Name ) AS a

数据如图：

4，这一行形成新的列，用PIVOT实现

SELECT * FROM (
 select sellerid,pay_type_name,cast(sum(amount) as decimal(18,2)) as payamout from (
 SELECT distinct oi.order_guid,ss.SellerId,bs.name AS pay_type_name,op.amount
 FROM dbo.shop_sellers AS ss
 LEFT JOIN dbo.order_item oi ON ss.SellerId=oi.tracking_id
 LEFT JOIN dbo.order_list ol ON ol.order_guid = oi.order_guid
 LEFT JOIN dbo.order_pay op ON ol.order_guid=op.order_guid
 LEFT JOIN dbo.base_pay_type bs ON op.pay_type_id=bs.pay_type_id
 INNER JOIN dbo.shops s ON s.ShopGuid=ol.owner
 WHERE bs.is_enabled=1 AND op.is_received=1 AND order_status='finished' and pay_status='paid' 
 and s.ShopId IN(SELECT ShopId FROM dbo.shops WHERE 1=1 and shopid=15 or ParentShopId=15) 
 AND ol.order_time between '2018-01-17' and '2018-08-17 23:59:59') a
 GROUP BY SellerId,pay_type_name) AS PA PIVOT(MAX( payamout ) FOR 
 pay_type_name IN ([现金],[支付宝],[微信支付],[会员卡],[康品汇会员卡],[银联扫码支付]))PPA

数据如图：

5，C#后台代码，先将一列转换成一行，以逗号隔开，【】包裹

string SQL = "SELECT LEFT(a.Name,LEN(a.Name)-1) AS Name FROM (SELECT STUFF((SELECT  '[' + name + '],' FROM(SELECT name FROM dbo.base_pay_type WHERE is_enabled = 1) a  FOR  XML PATH('')  ), 1, 0, '') AS Name ) AS a";
DataTable dt = dbAccess.ExecuteTable(SQL);
string filwes = dt.Rows[0]["name"].ToString();
得到的结果如上面标题3,然后拼接SQL,将filwes作为参数输入下面SQL语句
SELECT * FROM (
select sellerid,pay_type_name,cast(sum(amount) as decimal(18,2)) as payamout from (
SELECT distinct oi.order_guid,ss.SellerId,bs.name AS pay_type_name,op.amount
FROM dbo.shop_sellers AS ss
LEFT JOIN dbo.order_item oi ON ss.SellerId=oi.tracking_id
LEFT JOIN dbo.order_list ol ON ol.order_guid = oi.order_guid
LEFT JOIN dbo.order_pay op ON ol.order_guid=op.order_guid
LEFT JOIN dbo.base_pay_type bs ON op.pay_type_id=bs.pay_type_id
INNER JOIN dbo.shops s ON s.ShopGuid=ol.owner
WHERE bs.is_enabled=1 AND op.is_received=1 AND order_status='finished' and pay_status='paid' 
and s.ShopId IN(SELECT ShopId FROM dbo.shops WHERE 1=1 {1}) {2}) a
GROUP BY SellerId,pay_type_name) AS PA PIVOT(MAX( payamout ) FOR pay_type_name IN (‘“+filwes+”’))PPA