【JSP】05 请求转发

最新推荐文章于 2024-05-11 16:13:48 发布

原创最新推荐文章于 2024-05-11 16:13:48 发布 · 231 阅读

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文章标签：

#java #servlet #前端

该代码展示了如何在JavaServlet中进行请求转发。在RequestDemo5类中，接收到请求后设置数据并使用requestDispatcher转发到RequestDemo6。在RequestDemo6中，接收转发请求并获取存储的数据。

/**
 * 请求转发
 */
@WebServlet("/req5")
public class RequestDemo5 extends HttpServlet {
    @Override
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        System.out.println("demo5.....");

        // 存储数据
        request.setAttribute("msg","hello");

        // 请求转发
        request.getRequestDispatcher("/req6").forward(request,response);
    }

    @Override
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        this.doGet(request, response);
    }
}

/**
 * 请求转发
 */
@WebServlet("/req6")
public class RequestDemo6 extends HttpServlet {
    @Override
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        System.out.println("demo6....");
        // 获取数据
        Object msg = request.getAttribute("msg");
        System.out.println(msg);
    }

    @Override
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        this.doGet(request, response);
    }
}