POJ-1782 Run Length Encoding-相同字符个数_poj

本文介绍了一种简单的 RunLength 编码方法，并提供了一个 C 语言实现的例子。该算法能够有效压缩文本数据，通过计数连续重复的字符来减少存储空间。文章详细解释了编码规则，并附带了一个完整的源代码示例。

Run Length Encoding

Time Limit: 1000MS		Memory Limit: 30000K
Total Submissions: 4331		Accepted: 1406

Description

Your task is to write a program that performs a simple form of run-length encoding, as described by the rules below.

Any sequence of between 2 to 9 identical characters is encoded by two characters. The first character is the length of the sequence, represented by one of the characters 2 through 9. The second character is the value of the repeated character. A sequence of more than 9 identical characters is dealt with by first encoding 9 characters, then the remaining ones.

Any sequence of characters that does not contain consecutive repetitions of any characters is represented by a 1 character followed by the sequence of characters, terminated with another 1. If a 1 appears as part of the sequence, it is escaped with a 1, thus two 1 characters are output.

Input

The input consists of letters (both upper- and lower-case), digits, spaces, and punctuation. Every line is terminated with a newline character and no other characters appear in the input.

Output

Each line in the input is encoded separately as described above. The newline at the end of each line is not encoded, but is passed directly to the output.

Sample Input

AAAAAABCCCC
12344

Sample Output

6A1B14C
11123124

Source

Ulm Local 2004

#include<stdio.h>
#include<string.h>
int main()//空格也算字符
{
    char str[200];
    int i,j,cnt;
    while(gets(str))
    {
        if (!str[0])
        {
            putchar(10);
            continue;
        }
        cnt=1;
        for(i=0; str[i]; i++)
        {
            if (str[i] == str[i+1])
            {
                for ( j = i ; str[i] == str[i+1] && (i-j) < 8 ; i++ );
                printf("%d%c", i-j+1, str[i]);
            }
            else
            {
                printf("1");
                for(j=i; str[j]; j++)
                {
                    if(str[j]!=str[j+1])
                    {
                        if(str[j]=='1')
                            printf("1");
                        printf("%c",str[j]);
                    }
                    else
                        break;
                }
                printf("1");
                i=j-1;
            }
        }
        printf("\n");
        memset(str, 0, sizeof(str));
    }
    return 0;
}