HDOJ1001 Sum Problem_C++

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本文介绍了一个简单的在线评测平台HDOJ上的求和问题，任务是计算从1到n的所有整数之和。文章提供了完整的C++代码实现，并强调了输出格式的重要性。

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Sum Problem

Time Limit: 1000/500 MS (Java/Others)

Memory Limit: 65536/32768 K (Java/Others)

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Description

Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.

Input

The input will consist of a series of integers n, one integer per line.

Output

For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.

Sample Input

1
100

Sample Output

1

5050

水题，直接贴代码吧

#include<iostream>
using namespace std;
int sum(int n)
{
int sum=0;
for(int i=1;i<=n;i++)
{
sum=sum+i;

}
return sum;
}
int main()
{
int n;
while(cin>>n)
{
cout<<sum(n)<<endl<<endl; //按照题目要求，换行符一定要2个，否则会presentation error
}

return 0;
}