要求:使用程序实现数据库成员的增删改查、
程序:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sqlite3.h>
void do_insert(sqlite3 * db);
void do_delete(sqlite3* db);
void do_update(sqlite3* db);
int main(int argc, const char *argv[])
{
//创建并且打开一个数据库
sqlite3* db=NULL;
if(sqlite3_open("./sq.db",&db)!=SQLITE_OK)
{
fprintf(stderr,"sqlite3_open failed:%d:%s\n",\
sqlite3_errcode(db),sqlite3_errmsg(db));
return -1;
}
printf("sqlite3_open success\n");
//创建一个表格:数据库中的sql语句怎么写,该字符串就怎么写
char sql[128]="create table if not exists stu (id int,name char,score float);";
char *errmsg=NULL;
if(sqlite3_exec(db,sql,NULL,NULL,&errmsg)!=SQLITE_OK)
{
fprintf(stderr,"line:%d sqlite3_exec:%s\n",__LINE__,errmsg);
return -1;
}
printf("table stu create success\n");
char choose=0;
while(1)
{
system("clear");
printf("*********功能选项*********\n");
printf("**********1.插入**********\n");
printf("**********2.删除**********\n");
printf("**********3.修改**********\n");
printf("**********4.查询**********\n");
printf("**********5.退出**********\n");
printf("**************************\n");
printf("请输入>>>");
choose=getchar();
while(getchar()!=10);
switch(choose)
{
case '1':
do_insert(db);
break;
case '2':
do_delete(db);
break;
case '3':
do_update(db);
break;
case '4':
// do_select();
break;
case '5':
goto END;
break;
default:
printf("输入错误,请重新输入\n");
}
printf("请输入任意字符串清屏>>>");
while(getchar()!=10);
}
END:
if(sqlite3_close(db)!=SQLITE_OK)
{
fprintf(stderr,"line:%d sqlite3_close:%d:%s\n",\
__LINE__,sqlite3_errcode(db),sqlite3_errmsg(db));
return -1;
}
return 0;
}
void do_insert(sqlite3* db)
{
int id=0;
char buf[20]="";
float score=0;
printf("请输入要插入的id号>>>");
scanf("%d",&id);
while(getchar()!=10);
printf("请输入要插入的姓名>>>");
fgets(buf, sizeof(buf), stdin);
buf[strlen(buf)-1] = 0;
printf("请输入要插入的分数>>>");
scanf("%g",&score);
while(getchar()!=10);
char sql[128]="";
sprintf(sql,"insert into stu values (%d,'%s',%g);",id,buf,score);
char *errmsg=NULL;
if(sqlite3_exec(db,sql,NULL,NULL,&errmsg)!=SQLITE_OK)
{
fprintf(stderr,"line:%d sqlite3_exec:%s\n",__LINE__,errmsg);
return;
}
printf("insert into stu success\n");
return;
}
void do_delete(sqlite3* db)
{
int id=0;
char sql[128]="";
printf("请输入要删除同学的id号>>>");
scanf("%d",&id);
while(getchar()!=10);
sprintf(sql,"delete from stu where id=%d",id);
char *errmsg=NULL;
if(sqlite3_exec(db,sql,NULL,NULL,&errmsg)!=SQLITE_OK)
{
fprintf(stderr,"line:%d sqlite3_exec:%s\n",__LINE__,errmsg);
return;
}
printf("delete success\n");
return;
}
void do_update(sqlite3* db)
{
int id=0;
char sql[128]="";
char buf[20]="";
float score=0;
int choose=0;
char *errmsg=NULL;
printf("请输入要修改的选项:1.id,2.name,3.score>>>");
choose=getchar();
while(getchar()!=10);
switch(choose)
{
case '1':
printf("请输入同学的姓名>>>");
fgets(buf, sizeof(buf), stdin);
buf[strlen(buf)-1] = 0;
printf("请输入修改后的id号>>>");
scanf("%d",&id);
while(getchar()!=10);
sprintf(sql,"UPDATE stu SET id=%d WHERE name='%s'",id,buf);
if(sqlite3_exec(db,sql,NULL,NULL,&errmsg)!=SQLITE_OK)
{
fprintf(stderr,"line:%d sqlite3_exec:%s\n",__LINE__,errmsg);
return;
}
printf("update success\n");
break;
case '2':
printf("请输入id号>>>");
scanf("%d",&id);
while(getchar()!=10);
printf("请输入修改后的姓名>>>");
fgets(buf, sizeof(buf), stdin);
buf[strlen(buf)-1] = 0;
sprintf(sql,"UPDATE stu SET name='%s' WHERE id=%d",buf,id);
if(sqlite3_exec(db,sql,NULL,NULL,&errmsg)!=SQLITE_OK)
{
fprintf(stderr,"line:%d sqlite3_exec:%s\n",__LINE__,errmsg);
return;
}
printf("update success\n");
break;
case '3':
printf("请输入同学id>>>");
scanf("%d",&id);
while(getchar()!=10);
printf("请输入想要修改后的分数>>>");
scanf("%g",&score);
while(getchar()!=10);
sprintf(sql,"UPDATE stu SET score=%g WHERE id=%d",score,id);
if(sqlite3_exec(db,sql,NULL,NULL,&errmsg)!=SQLITE_OK)
{
fprintf(stderr,"line:%d sqlite3_exec:%s\n",__LINE__,errmsg);
return;
}
printf("update success\n");
break;
default:
printf("输入错误,请重新输入\n");
}
return;
}
效果实现:
插入选项:
删除选项:
修改选项: