Java 小白通过Lambda表达式执行Cook的makeFood方式

public class TestDemo03 {
    public static void main(String[] args) {
        invokeMakeFood(()-> {
                System.out.println("火锅");
        });

    }public static void invokeMakeFood(Cook cook){
        cook.makeFood();
    }
}
public interface Cook {
    public void makeFood();
}