# @Time:2020/12/15 23:32
# @Author:李 祥
# @File:Set.py
# @Software:PyCharm
# set和dict类似,也是一组key的集合,但没有value。key唯一性且无序
s1 = set() # 空集合 只能用set()
print(s1, type(s1))
s1 = {1, 2, 3}
print(s1, type(s1))
# 集合:无序
s1 = {1, 2, 3}
s2 = {3, 2, 1}
print(s1, type(s1)) # {1, 2, 3}
print(s2, type(s2)) # {1, 2, 3}
# 集合:唯一
s1 = {1, 1, 2, 3, 3}
print(s1)
# 集合:存放不可变(key)
s1 = {1, 2, 3, False, "4"} # 字典存放多种数据类型
print(s1)
# list1 = [1, 2, 3] # 列表可变 存放报错
# s2 = {1, list1}
# print(s2)
# dic1 = {1: 2} # 字典可变 存放报错
# s3 = {1, dic1}
# print(s3)
tuple1 = (1, 2, 3)
s3 = {1, tuple1}
print(s3)
集合的操作
增
s1 = {1, 2, 3}
print(s1, id(s1))
s1.add(4)
print(s1, id(s1))
# 指定序列,依次加入到集合
s1 = {1, 2, 3}
s1.update("abc")
print(s1, id(s1))
s1 = {1, 2, 3}
list1 = ["a", "b", "c"]
s1.update(list1)
print(s1, id(s1))
# 删 clear remove discard pop
s1 = {1, 2, 3}
s1.clear() # 清空
print(s1)
s1 = {1, 2, 3}
s1.remove(1) # 移除元素。移除不存在的元素,报错:keyError。不可给定默认值
# s1.discard(4) # 如果没有找到,不做任何操作
print(s1)
s1 = {1, 2, 3}
a = s1.pop() # 随机弹出一个元素,每次都不一定相同
print(a)
print(s1)
# 改:先删除后增加
s1 = {1, 2, 3}
s1.remove(1)
s1.add(4)
print(s1)
# 遍历
s1 = {1, 2, 3}
for i in s1:
print(i)
# 包含 in not in
s1 = {1, 2, 3}
res = 1 not in s1
print(res)
# 集合的运算 高中知识(交、并、差、补)
s1 = {1, 2, 3, 4}
s2 = {3, 4, 5, 6}
# 集合的运算交 & 或者 intersection
result = s1 & s2
# result = s1.intersection(s2)
print(result)
# 集合的运算并 | 或者 union
result = s1 | s2
# result = s1.union(s2)
print(result)
# 集合的运算差 - 或者 difference
result = s1 - s2
# result = s1.difference(s2)
print(result)
# 集合的运算异或集(对称差集) ^ 或者 symmetric_difference
result = s1 ^ s2
# result = s1.symmetric_difference(s2)
print(result)
# 子集
a = {1, 2}
b = {1, 2, 3, 4}
result = a <= b
# result= a.issubset(b) 同a<=b
# result= b.issuperset(a) 同a<=b
print(result)
# 不相交 isdisjoint
s1 = {1, 2, 3, 4}
s2 = {3, 4, 5, 6}
result = s1.isdisjoint(s2)
print(result)
# 应用
# 列表应用
num = [1, 1, 2, 3, 3]
s = set(num) # 注意:顺序可能打乱
res = list(s)
print(res)
# 冰冻集合 frozenset
# 强制转化为冰冻集合
# 一旦创建,不能进行任何修改,只能用于集合运算操作
s = frozenset()
print(s, type(s))
s1 = [1, 2, 3]
s1 = "abc"
s2 = frozenset(s1)
print(s2, type(s2))
# s2.add(4) # 报错
s3 = frozenset("4")
print(s2 & s3)
Python基础_集合
Python集合操作详解及应用
最新推荐文章于 2025-05-16 11:00:00 发布
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