Syntax:
Description:
The strtok() function returns a pointer to the next "token" in str1, where str2 contains the delimiters that determine the token. strtok() returns NULL if no token is found. In order to convert a string to tokens, the first call to strtok() should have str1 point to the string to be tokenized. All calls after this should have str1 be NULL.
Example:
#include <string.h> char *strtok( char *str1, const char *str2 );
Description:
The strtok() function returns a pointer to the next "token" in str1, where str2 contains the delimiters that determine the token. strtok() returns NULL if no token is found. In order to convert a string to tokens, the first call to strtok() should have str1 point to the string to be tokenized. All calls after this should have str1 be NULL.
Example:
char str[] = "now # is the time for all # good men to come to the # aid of their country";
char delims[] = "#";
char *result = NULL;
result = strtok( str, delims );
while( result != NULL ) {
printf( "result is /"%s/"/n", result );
result = strtok( NULL, delims );
}
OUTPUT:
result is "now "
result is " is the time for all "
result is " good men to come to the "
result is " aid of their country"
本文介绍了如何使用C语言中的strtok函数来将一个字符串分解为多个子串(令牌)。通过一个具体的示例展示了strtok函数的基本用法,包括如何初始化函数调用以及如何迭代获取每个子串。
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