Codeforces Round #438 B Race Against Time（模拟）

题目链接：点击打开链接

一个基于时钟的模拟题，将时钟分为3600份，从起点分别顺时针和逆时针走一遍即可

AC代码：

#include <iostream>
#include <cstdio>
#include <cstring>
#include <algorithm>

using namespace std;


int clock[3601];
int h, m, s, t1, t2;

void solve()
{
    memset(clock,0,sizeof(clock));
    if(m==0)    m=60;
    if(s==0)    s=60;
    clock[(m*60+s)%3601]=-1, clock[s*60]=-1;
    clock[(300*h+m+(s+59)/60)%3601]=-1;
    for(int i=t1*300;!clock[i%3601];i++)
          clock[i%3601]=1;
    for(int i=t1*300-1;!clock[i%3601];i--)
       {
          if(i==0) i=3600;
          clock[i%3601]=1;
       }
    if(clock[t2*300])   cout<<"YES"<<endl;
    else    cout<<"NO"<<endl;
}

int main()
{
    ios::sync_with_stdio(0);
    cin.tie(0);
    while(cin>>h>>m>>s>>t1>>t2)
    {
        solve();
    }
    return 0;
}