不错的sql

1.有员工表empinfo
(
Fempno varchar2(10) not null pk,
Fempname varchar2(20) not null,
Fage number not null,
Fsalary number not null
);
假如数据量很大约1000万条；写一个你认为最高效的SQL，用一个SQL计算以下四种人：
fsalary>9999 and fage > 35
fsalary>9999 and fage < 35
fsalary <9999 and fage > 35
fsalary <9999 and fage < 35
每种员工的数量；
select sum(case when fsalary > 9999 and fage > 35
then 1
else 0end) as "fsalary>9999_fage>35",
sum(case when fsalary > 9999 and fage < 35
then 1
else 0
end) as "fsalary>9999_fage<35",
sum(case when fsalary < 9999 and fage > 35
then 1
else 0
end) as "fsalary<9999_fage>35",
sum(case when fsalary < 9999 and fage < 35
then 1
else 0
end) as "fsalary<9999_fage<35"
from empinfo;