HDU 1001 Sum Problem 水题

Sum Problem

Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 440436    Accepted Submission(s): 110576


Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
 

Input
The input will consist of a series of integers n, one integer per line.
 

Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
 

Sample Input
  
1 100
 

Sample Output
  
1 5050
 

Author
DOOM III
 

Recommend
We have carefully selected several similar problems for you:   1002  1003  1004  1092  1089 


水题 打表就可以过
#include <stdio.h>

long long a[1000000]={0};
int main()
{
	long long i,j,n;
	
	for(i=1;i<1000000;i++)
	{
		a[i]=i+a[i-1];
	}
	while(~scanf("%I64d",&n))
	{
		printf("%I64d\n\n",a[n]);
	}
	
	return 0;
}


评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值