hdu 1228 A+B

A + B

  HDU - 1228 

读入两个小于100的正整数A和B,计算A+B. 
需要注意的是:A和B的每一位数字由对应的英文单词给出. 

Input
测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出. 

Output
对每个测试用例输出1行,即A+B的值. 

Sample Input

one + two =
three four + five six =
zero seven + eight nine =
zero + zero =

Sample Output

3
90
96

#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std;
int main()
{
	char s[50];
	while(gets(s)>0)
	{
		int len=strlen(s);
		int a=0,b;
		for(int i=0;i<len;i++)
		{
			if(s[i]=='+')
			{
				b=a;
				a=0;
			}
			if(memcmp(s+i,"one",3)==0)
				a=a*10+1,i+=3;
			else if(memcmp(s+i,"two",3)==0)
				a=a*10+2,i+=3;
			else if(memcmp(s+i,"three",5)==0)
				a=a*10+3,i+=5;
			else if(memcmp(s+i,"four",4)==0)
				a=a*10+4,i+=4;
			else if(memcmp(s+i,"five",4)==0)
				a=a*10+5,i+=4;
			else if(memcmp(s+i,"six",3)==0)
				a=a*10+6,i+=3;
			else if(memcmp(s+i,"seven",5)==0)
				a=a*10+7,i+=5;
			else if(memcmp(s+i,"eight",5)==0)
				a=a*10+8,i+=5;
			else if(memcmp(s+i,"nine",4)==0)
				a=a*10+9,i+=4;
			else if(memcmp(s+i,"zero",4)==0)
				a=a*10+0,i+=4;
		}
		if(a+b==0)
			break;
		printf("%d\n",a+b);
	}
	return 0;
}