3.【难题】按导演分组计算销售总额,求出平均销售额冠军(统计结果过滤掉只有单部电影的导演,列出导演名,总销量,电影数量,平均销量)
--请输入sql
SELECT director,
sum(Domestic_sales+International_sales) as total_sales,
count(*) as movies,
sum(Domestic_sales+International_sales)/count(*) as avg_sales
from movies join boxoffice
on movies.id=boxoffice.movie_id
group by director
having count(*)>1
order by avg_sales desc
limit 1
4.【变态难】找出每部电影和单部电影销售冠军之间的销售差,列出电影名,销售额差额
select title,
top.top_sales - (Domestic_sales+International_sales) as diff_sales
from movies
left join boxoffice
on id = movie_id
cross join
(SELECT max(Domestic_sales+International_sales) as top_sales
from boxoffice)
as top
用到了一个cross join 交叉连接(笛卡尔积),单部电影的销冠作为一张单独的表。
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