python获取重复和不重复的元素的角标

1、获取重复元素及其角标位置

a = [2,3,8,9,1,2,7,1,3,1,4,7]
b = set()
for i in a:
    if a.count(i)>1:
        b.update([i])
        
def return_dict(x):
    dict = {}
    for j in x:
        list = []
        for A in range(len(a)):
            if j == a[A]:
                list.append(A)
        dict[j] = list
    return dict
​
print(return_dict(b))

2、获取所有元素的角标位置

(1)直接通过集合过滤

a = [2,3,8,9,1,2,7,1,3,1,4,7]
b = set(a)
print(return_dict(b))

(2) 通过判断获取

a = [2,3,8,9,1,2,7,1,3,1,4,7]
b = set()
for i in a:
    if a.count(i)>0:
        b.update([i])
​
print(return_dict(b))

3、分别获取重复和不重复的元素的角标

a = [2,3,8,9,1,2,7,1,3,1,4,7]
b = set()
c = set()
for i in a:
    if a.count(i)>1:
        b.update([i])
    else:
        c.update([i])
        
print(return_dict(b))
print(return_dict(c))